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Murrr4er [49]
3 years ago
5

Doctors checked four dishwasher handles. Three of them tested positive for the rhinovirus. What percentage of the dishwasher han

dles tested positive for the rhinovirus?
Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0
The answer is 3/4...........
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What is the probability that a randomly selected house with 2 bathrooms has 3 bedrooms?
coldgirl [10]
From the table there is 24 houses with 2 bathrooms and 3 bedrooms

there is a total of 30 houses with 2 bathrooms

 the probability is 24 /30 = 0.8

7 0
2 years ago
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What is the probability of surviving 6.5 years?
Eddi Din [679]
There is not a formula for everything need more data
7 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
Ksju [112]

Answer:

3.162 units

Step-by-step explanation:

First identify the points that undergo transformation

You have;

A = (0,0)   and B =(1,3)

The transformation is T: (x,y)= (x+2, y+1), this means to get the image you add the x coordinate of the object to 2, and the y coordinate to 1.

<u>Finding coordinates of the image points A' and B' </u>

A'= (0+2,0+1) = (2,1)

B'=(1+2, 3+1)=(3,4)

<u>Finding the distance A'B'</u>

The formula for distance d is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

where

x₁=2

x₂=3

y₁=1

y₂=4

d=distance between two points

Applying the formula

d=\sqrt{(3-2)^2+(4-1)^2} \\\\\\d=\sqrt{1^2+3^2} \\\\\\d=\sqrt{1+9} \\\\\\d=\sqrt{10} \\\\\\d=3.162

The distance A'B' is √10 =3.162 units

8 0
3 years ago
Read 2 more answers
The ratio of boys to girls in band class was 3 to 5. If there were 24 boys. How many girls were in band class?
Tamiku [17]

Answer:

40 girls

Step-by-step explanation:

Set up a proportion where x is the number of girls in band class:

\frac{3}{5} = \frac{24}{x}

Cross multiply and solve for x:

3x = 120

x = 40

So, there were 40 girls in band class.

7 0
2 years ago
Read 2 more answers
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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