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3 years ago

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look that the picture PLSSSS HEELP IM IN A TEST I DID NOT STUDY FOR PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS

SSSSSSSSSSSSSSSSSSSSSSSSSSS

1 answer:

max2010maxim [7]3 years ago

4 0

Answer:

1. a

2. d

3. c

4. d?

5. cant answer cause I cannot see the data

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Enya walked 2km 309m from school to the store. Then, she walked from the store to her home. If she walked a total of 5km, how fa

RSB [31]

Answer:

2 km 691 m

Step-by-step explanation:

5 km - 2 km 309 m

= 5000 m - 2309 m

= 2691 m

= 2 km 691 m

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2 years ago

Evan wants to buy a digital camera that sells for $199.99 if he uses his dicount card he will save 18%. about how much will he s

ikadub [295]

35.99 ROUND IT OFF TO 36.00 SO THAT MEANS HE PAID 163.99
199.99X 18/100
3599.85/100
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3 years ago

Suppose that you buy a bond with face value $1,000 that was originally issued 18 months ago. The maturity date is 4 years from t

ziro4ka [17]

Answer:

Step-by-step explanation:

Interest earned during the rest of 2 years and 6 months

40 + 40 + 40 = 120

he will be getting 1000 at the time of maturity ie after 2.5 years .

Total receipt = 1000 + 120 = 1120

investment made = 820

total receipt earned = 1120

profit made = 300

time = 2.5 years

profit = investment x rate of intt x time / 100

300 = 820 x r x 2.5 / 100 where r is rate of interest

r = 30000 / 820 x 2.5

= 14.63 % .

4 0

3 years ago

Find the x intercept and the y intercept of -x+2y=8

vekshin1

Answer:

Hope this helps

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago