If a box has a square base its volume will be:
V=hb^2 where h is the height...
h=V/b^2 we are told that V=125 so
h=125/b^2 now for the surface area, which consists of the two bases for a total of 2b^2. It will also have four sides with a total area of 4(bh)=4bh so
A=2b^2+4bh, using h found above in this gives us:
A=2b^2+4b(V/b^2)
A=2b^2+4V/b
A=(2b^3+4V)/b, then taking the derivatives we can find the velocity of the area function.
dA/db=(6b^3-2b^3-4V)/b^2
dA/db=(4b^3-4V)/b^2
dA/db=0 when 4b^3-4V=0
b^3=V
b=V^(1/3), since V=125
b=5in, and since h=V/b^2
h=125/25=5in
So the dimensions that will minimize the amount of material used to enclose a volume of 125in^2 is a 5in cube.
h=b=5in
Answer:
I think that Nick is correct because you are going to have to make your answer positive and when you do the two fractions -4/9 + -6/9 are going to be 6/9 + 4/9 and there is already a addition sign in the last problem we are just going to keep it there. And when we add we get 10/9 or 1 1/9
If i get it wrong please don't hate im just in 7 grade ok :(
Answer:she wins 2 marbles
Step-by-step explanation:
Answer:
3 x 34 = 102 + 2 = 104 is your answer just do the equation
<span>Set the two equations for y equal to each other. Solve for x. This will be the x-coordinate for the point of intersection. Use this x-coordinate and plug it into either of the original equations for the lines and solve for y.</span>
