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Alex777 [14]
4 years ago
8

An airplane is at a location 800 miles due west of city X. Another airplane is at a distance of 1,200 miles southwest of city X.

The angle at city X created by the paths of the two planes moving away from city X measures 60°. What is the distance between the two airplanes to the nearest mile? Assume that the planes are flying at the same altitude.
Mathematics
1 answer:
zaharov [31]4 years ago
6 0

Answer:

The distance between the two airplanes (to the nearest mile) is 1058 miles.

Step-by-step explanation:

An airplane A is at a location 800 miles due west of city X. So AX = 800 miles.

Another airplane is at a distance of 1,200 miles southwest of city X. So BX = 1200 miles.

The angle at city X created by the paths of the two planes moving away from city X measures 60°. So angle ∠AXB = 60°.

In triangle ΔAXB, AX = 800 miles, BX = 1200 miles, ∠AXB = 60°.

Using law of cosines:-

AB² = AX² + BX² - 2 * AX * BX * cos(∠AXB).

AB² = 800² + 1200² - 2 * 800 * 1200 * cos(60°).

AB² = 640000 + 1440000 - 2 * 960000 * 1/2

AB² = 2080000 - 960000

AB² = 1120000

AB = √(1120000) = 1058.300524

Hence, the distance between the two airplanes (to the nearest mile) is 1058 miles.

Read more on Brainly.com - brainly.com/question/12103659#readmore

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a set of average city temperatures in december are normally distributed with a mean of 16.3°C and a standard deviation of 2°C. w
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Answer:

19.74% of temperatures are between 12.9°C and 14.9°C

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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In this question, we have that:

\mu = 16.3, \sigma = 2

What proportion of temperatures are between 12.9°C and 14.9°C?

This is the pvalue of Z when X = 14.9 subtracted by the pvalue of Z when X = 12.9.

X = 14.9

Z = \frac{X - \mu}{\sigma}

Z = \frac{14.9 - 16.3}{2}

Z = -0.7

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X = 12.9

Z = \frac{X - \mu}{\sigma}

Z = \frac{12.9 - 16.3}{2}

Z = -1.7

Z = -1.7 has a pvalue of 0.0446

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