Answer:
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.
Step-by-step explanation:
given that Ty and Gajge are football players.
Carries is 15 for both and average is the same 4 for both.
But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.
Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)
But for Gajge, highest is 19 and lowest is 2.
i.e. range = 19-2 =17 very much higher than that of Ty
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.
Answer:
19/24
Step-by-step explanation:
slope = rise/run = (y1 - y2) / (x1 - x2)
s = (19 - 0) / (8 - -16)
s = 19/24
Answer:
(11√3)/3
Step-by-step explanation:
In order to solve for the variable, you will need to use a trig function. In this case, you will need to use the trig function tangent.
Tan = opposite/adjacent
⇒ Tan 30° = x/11
⇒ 11 · Tan 30° = x
⇒ (11√3)/3 = x
The rate of change is 16.8 million tons per year
<em><u>Solution:</u></em>
Given that, the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons
<em><u>The average rate of change is given by formula:</u></em>
Value in 1950 = 12 million tons
Value in 1955 = 96 million tons
Change in value = value in 1955 - value in 1950
Change in value = 96 million - 12 million = 84 million tons
Number of years = 1950 to 1955 = 5 years
<em><u>Substitute the given values in formula,</u></em>
<em><u></u></em>
<em><u></u></em>
Thus rate of change is 16.8 million tons per year
