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san4es73 [151]
2 years ago
9

A line has a y-intercept of 19 and a slope of 9/4. Find the equation of the line.

Mathematics
1 answer:
Taya2010 [7]2 years ago
3 0

Answer:

y=9/4x+19

Step-by-step explanation:

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What is 3/18 divided by 7/21... help plz
saw5 [17]
3/18 divided 7/21 =3/18 multiply by 21/7 (we have to flip the second fraction and multiply by 3/18)= 63/126=1/2
So the answer is 1/2
8 0
3 years ago
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Given functions f and g, find f-g.
Eva8 [605]

Answer:

-5x-5

Step-by-step explanation:

original functions:

f(x)=3x-8\\g(x)=8x-3

Subtract the polynomials:

f(x)-g(x) = (3x-8) - (8x-3)

Distribute the negative sign:

3x-8-8x+3

Combine like terms:

(3x-8x)+(-8+3)

Add like terms:

-5x-5

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2 years ago
What is 3 quarters of 20?
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Well, one quarter of 20 is 5 (because 20 ÷ 4 = 5).  so, to find 3 quarters, we multiply 5 times 3.

5 × 3 = 15, so 3 quarters of 20 is 15.
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3 years ago
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Caroline is taking a multiple choice test with a total of 40 points available. Each question is worth exactly 5 points. What wou
Leno4ka [110]

Answer:

30

40 - 5x

Step-by-step explanation:

Caroline is taking test worth 40 points that has 5 points per question.  If she got 2 questions wrong, she would have a score of `30.

2 × 5 = 10

40 - 10 = 30

If Caroline got x questions wrong, she would have a score of 40 - 5x.

5 0
3 years ago
Dilate the trapezoid using center (-3,4) and scale factor 1/2.
pochemuha

The coordinates of the vertices of the image of the trapezoid are given as;

A'(x, y) = (- 4, 1), B'(x, y) = (- 2, 1), C'(x, y) = (- 5 / 2, 5 / 2) , D'(x, y) = (- 7 / 2, 5 / 2).

<h3>How to find the image of a trapezoid by dilation?</h3>

In this question we have a representation of a trapezoid, whose image has to be generated by a kind of rigid transformation known as dilation, whose equation is described :

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]

Where O(x, y) - Center of dilation

k - Scale factor

And P(x, y) - Coordinates of the original point, P'(x, y) - Coordinates of the resulting point.

Since k = 1 / 2, A(x, y) = (- 5, - 2), B(x, y) = (- 1, - 2), C(x, y) = (- 2, 1), D(x, y) = (- 4, 1), O(x, y) = (- 3, 4),

Therefore, the coordinates of the vertices of the image are:

Point A'

A'(x, y) = O(x, y) + k · [A(x, y) - O(x, y)]

A'(x, y) = (- 3, 4) + (1 / 2) [(- 5, - 2) - (- 3, 4)]

A'(x, y) = (- 3, 4) + (1 / 2)  (- 2, - 6)

A'(x, y) = (- 3, 4) + (- 1, - 3)

A'(x, y) = (- 4, 1)

Point B';

B'(x, y) = O(x, y) + k [B(x, y) - O(x, y)]

B'(x, y) = (- 3, 4) + (1 / 2) [(- 1, - 2) - (- 3, 4)]

B'(x, y) = (- 3, 4) + (1 / 2)  (2, - 6)

B'(x, y) = (- 3, 4) + (1, - 3)

B'(x, y) = (- 2, 1)

Point C';

C'(x, y) = O(x, y) + k · [C(x, y) - O(x, y)]

C'(x, y) = (- 3, 4) + (1 / 2)  [(- 2, 1) - (- 3, 4)]

C'(x, y) = (- 3, 4) + (1 / 2) (1, - 3)

C'(x, y) = (- 3, 4) + (1 / 2, - 3 / 2)

C'(x, y) = (- 5 / 2, 5 / 2)

Point D'

D'(x, y) = O(x, y) + k  [D(x, y) - O(x, y)]

D'(x, y) = (- 3, 4) + (1 / 2) [(- 4, 1) - (- 3, 4)]

D'(x, y) = (- 3, 4) + (1 / 2) (- 1, - 3)

D'(x, y) = (- 3, 4) + (- 1 / 2, - 3 / 2)

D'(x, y) = (- 7 / 2, 5 / 2)

To learn more on dilations:

brainly.com/question/13176891

#SPJ1

3 0
1 year ago
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