What is the question exactly?
Very interesting question!
Let's try to get something that would work for just 5 for now.
Any of these numbers would leave a remainder of 1 when divided by just 5:
6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61, 66, 71, 76, 81, 86, ...
Notice that they all look like 5*(something) + 1. Basically, they are all multiples of 5 plus 1.
Let's see what would work for just 8:
9, 17, 25, 33, 41, 49, 57, 65, 73, 81, 89, ...
Are there any matches... AHA! It's 81. This is the lowest positive integer greater than 1 that follows the rule for both 5 and 8.
-3(2x-4)+8x-8
-6x+12+8x-8
2x+4
x=2
Answer:
y + 11 = 14
Step-by-step explanation:
Answer:
x = 4
Step-by-step explanation:
y = - 2 is the equation of a horizontal line parallel to the x- axis.
A perpendicular line is therefore a vertical line parallel to the y- axis with equation
x = c
where c is the value of the x- coordinates the line passes through.
The line passes through (4, - 2 ) with x- coordinate 4 , thus
x = 4 ← equation of perpendicular line
