3 years ago

The altitudes of a triangle _________ meet inside the triangle. *

Mathematics

1 answer:

docker41 [41]3 years ago

3 0

Answer:

sometimes

Step-by-step explanation:

The three altitudes in an acute triangle all lie in the interior of the triangle and intersect inside the triangle. Two of the three altitudes in a right triangle are the legs of the triangle.

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If BC = 5 and CD = 26, find AC.

Blababa [14]

Answer:

$AC=\sqrt{130}$

Step-by-step explanation:

AC is the geometric mean. Solve it using this proportion:

$\frac{BC}{AC}=\frac{AC}{CD}$

Now fill in the values we know:

$\frac{5}{AC}=\frac{AC}{26}$

Cross multiply to get

$(AC)^2=130$

That means that

AC = $\sqrt{130}$ , which, in decimal form is

AC = 11.40175425

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dexar [7]

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A corporate team-building event costs $4 for every attendee. How many attendees can

Lunna [17]

It would be 9. Because each person has to pay 4$ so 9*4=36 or 36/4=9

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3 years ago

If f(n) = (2n + 3)2 – 2n, which statement is true?

viktelen [127]

Answer: f(5) = 16

Step-by-step explanation:

f(n) = (2n + 3)2 – 2n

f(5) = ((2 x 5) + 3)2 – 2 x 5

f(5) = (10 + 3)2 – 10

f(5) = (13)2 – 10

f(5) = 26 – 10

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4 years ago