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Naddika [18.5K]

3 years ago

5

Pls help this is not graded

1 answer:

egoroff_w [7]3 years ago

8 0

It’s probably b mmm I’m not sure though

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PLEASE HELP ME!!!!!!!!!

vaieri [72.5K]

Weekly compact: 18
Weekly standard: 25
Weekly full size: 36
Total weekly: 18 + 25 + 36 = 79

standard weekly as percent of total weekly:

25/79 * 100 = 31.6455...%

Answer: 32%

8 0

3 years ago

How do I find the x-intercept to this?<br><br> 9x + 12y= 36

Wewaii [24]

You can simply put the equation as 9x = 36 and divide by 9, then x = 4

4 0

3 years ago

Read 2 more answers

Help 17 points , explain please

Anni [7]

Answer:

∠6=58°

Step-by-step explanation:

∠3=∠6=58°

8 0

3 years ago

W = p ( y -z ) Please solve this for z.

11111nata11111 [884]

w = p(y - z)

divide p on both sides

$\frac{w}{p} = y - z$

Subtract y on both sides

$\frac{w}{p} - y = -z$

Divide -1 on both sides

$-\frac{w}{p} +y=z$

8 0

3 years ago

If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are:

Minimum ( $\cos \theta = 0$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0$

Maximum ( $\cos \theta = 1$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1$

With the help of a graphing tool we get the family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

7 0

3 years ago