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rodikova [14]
2 years ago
7

Find the equation of a line that is parallel to the line x= - 3 and contains the point (-8,6)

Mathematics
1 answer:
jeyben [28]2 years ago
5 0

m =  \frac{y - y1}{x - x1}  \\  - 3 =  \frac{y - 6}{x - ( - 8)}  \\  - 3 =  \frac{y - 6}{x + 8} \\ y - 6 =  - 3(x + 8) \\ y - 6 =  - 3x - 24 \\ y =  - 3x - 24 + 6 \\ y =  - 3x - 18

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