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2 years ago

Find the equation of a line that is parallel to the line x= - 3 and contains the point (-8,6)

1 answer:

5 0

$m = \frac{y - y1}{x - x1} \\ - 3 = \frac{y - 6}{x - ( - 8)} \\ - 3 = \frac{y - 6}{x + 8} \\ y - 6 = - 3(x + 8) \\ y - 6 = - 3x - 24 \\ y = - 3x - 24 + 6 \\ y = - 3x - 18$

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Number 18.

Rashid [163]

f(x) = -5/2x + 4

f(3) = (-5/2)(3) + 4

f(3) = -15/2 + 4

f(3) = -7.5 + 4

f(3) = -3.5

Answer: B. –3.5

4 0

2 years ago

Which of the following represents the most accurate estimation of 4+8

Helen [10]

4 + 8 = 12 that is the answer

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3 years ago

The Carson family sent 500 text messages last month. Mrs. Carson sent 15 text messages; Mr. Carson sent 1; Cathi sent 104; and B

Llana [10]

Answer:

76%

Step-by-step explanation:

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2 years ago

Which ordered pair is not a point on the graph of y=-x+5

Step2247 [10]

Answer: (1,1) (1,2))

Step-by-step explanation: Use desmos.com/calculator

3 0

3 years ago

Read 2 more answers

Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$

horrorfan [7]

Answer:

$A +B+C+D = 3$ is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

$A+B+C+D = ?$ if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under $\sqrt$ (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

$\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \ (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}$

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, $A +B+C+D = 5+6-10+2 = \bold3$

5 0

2 years ago