2 years ago

Find the equation of a line that is parallel to the line x= - 3 and contains the point (-8,6)

1 answer:

5 0

$m = \frac{y - y1}{x - x1} \\ - 3 = \frac{y - 6}{x - ( - 8)} \\ - 3 = \frac{y - 6}{x + 8} \\ y - 6 = - 3(x + 8) \\ y - 6 = - 3x - 24 \\ y = - 3x - 24 + 6 \\ y = - 3x - 18$

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