All categories

2 years ago

Determine whether any of the ratios below are proportional. 10/45, 20/90 and 6/27

Mathematics

1 answer:

RoseWind [281]2 years ago

7 0

Answer:

Yes, all three of them are proportional

Step-by-step explanation:

First, let's simplify them all the way:

10/45 = 2/9

20/90 = 2/9

6/27 = 2/9

All three of these ratios simplified down to their simplest form are 2/9, meaning that they are all proportional.

You might be interested in

What is the solution to the inequality 2x<20

Keith_Richards [23]

The given expression is

$2x$

We just have to divide by 2

$\begin{gathered} \frac{2x}{2}$ <h2>Hence, the solution is all real numbers less than 10.</h2>

8 0

9 months ago

I NEED AN ANSWER ASAP GIVING 20 POINTS FOR IT!!

DanielleElmas [232]

It’s 60 4x6=24x 2.5=60

4 0

3 years ago

Read 2 more answers

The number of adults who attend a county fair (measured in hundreds of people) is represented by the function a(d)=−0.3d2+4d+9 ,

Lesechka [4]

Given is the function for number of adults who visit fair at day 'd' after its opening, a(d) = −0.3d² + 4d + 9.

Given is the function for number of children who visit fair at day 'd' after its opening, c(d) = −0.2d² + 5d + 11.

Any function f(d) to find excess of children more than adults can be written as follows :-

f(d) = c(d) - a(d).

⇒ f(d) = (−0.2d² + 5d + 11) - (−0.3d² + 4d + 9)

⇒ f(d) = -0.2d² + 0.3d² + 5d - 4d + 11 - 9

⇒ f(d) = 0.1d² + d + 2

6 0

2 years ago

Read 2 more answers

The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.

gtnhenbr [62]

Answer:

a) $r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) $m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=4 $\sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501$

$r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5$

And the slope would be:

$m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

And we can find the intercept using this:

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

4 0

2 years ago

Simplify. (-1/2√2)(-6√18) 18 -18 -36

olga_2 [115]

Hey!

Your answer is solved below/above idk wherever just see in the picture.

8 0

2 years ago

Read 2 more answers