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jenyasd209 [6]
4 years ago
8

The length of a rectangle is 4cm, and the width is 1cm. find the length of a diagonal

Mathematics
1 answer:
olganol [36]4 years ago
7 0

\sqrt{5}
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A parallelogram has an area of 216.24 cm squared, and a height of 15.9 cm.
Kamila [148]
Area of <span>parallelogram 

A = bh
so
b = A/h
b = </span><span>216.24 / 15.9
</span>b = 13.6

answer
<span>base of the parallelogram = 13.9 cm</span>
7 0
4 years ago
Read 2 more answers
Please help asap!! will give brainlist :)
Naddik [55]

Yo sup??

Area of trapezium=1/2*(sum of opposite sides)*(height of trapezium)

=1/2*(12.5+17.5)*6

=1/2*30*6

=90 cm²

Therefore the correct answer is option A

Hope this helps.

8 0
3 years ago
Read 2 more answers
Point B(5, -6, -1) is translated using the transformation (x - 2, y + 3, z + 1). What are the coordinates of B´?
denpristay [2]
   
B(5 - 2, -6 + 3, -1 + 1) = B(3, -3, 0)



6 0
3 years ago
Write the cubic polynomial function f(x)in expanded form with zeros −6,−5,and −1, given that f(0)=60
RSB [31]

Answer:

f(x)=2x^{3}+24x^{2}+82x+60

Step-by-step explanation:

we know that

The roots of the polynomial are the values of x when the value of the polynomial f(x) is equal to zero

The roots of the polynomial function are

x=-6 -----> (x+6)=0

x=-5 -----> (x+5)=0

x=-1 -----> (x+1)=0

The equation of the cubic polynomial is

f(x)=a(x+6)(x+5)(x+1)

where

a is the leading coefficient

Remember that

f(0)=60

That means ------> For x=0 the value of f(x) is equal to 60

substitute the value of x and the value of y in the function and solve for a

60=a(0+6)(0+5)(0+1)

60=a(6)(5)(1)

60=30a

a=2

so

f(x)=2(x+6)(x+5)(x+1)

Applying the distributive property

Convert to expanded form                  

f(x)=2(x+6)(x+5)(x+1)\\\\f(x)=2(x+6)(x^{2}+x+5x+5)\\\\f(x)=2(x+6)(x^{2}+6x+5)\\\\f(x)=2(x^{3}+6x^{2}+5x+6x^{2}+36x+30)\\\\f(x)=2x^{3}+24x^{2}+82x+60

3 0
4 years ago
The value of 2 in 2,783 and 7,283
k0ka [10]
The 2 in 2783 is two thousand and the 2 in 7283 is 100

A way to remember is go from right to left!

ones, tens, hundred, and thousand
4 0
3 years ago
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