The length of a rectangle is 4cm, and the width is 1cm. find the length of a diagonal

While sorting some change into piggy banks, belle put 2 coins in the first piggy bank, 8 coins in the second piggy bank, 32 coin

Bond [772]

512 coins will be in the fifth piggy bank

6 0

3 years ago

Read 2 more answers

The sum of four consecutive integers is 286. Find the four integers

8_murik_8 [283]

Step 1: Write out the problem.
Step 1: Write out the problem.
Step 1: Write out the problem.
x+(x+1)+(x+2)+(x+3)= 286

Step 2: Take out the parentheses.
x+x+1+x+2+x+3= 286

Step 3: Combine like terms.
4x+6= 286

Step 4: Subtract 6 from both sides.
4x+6 -6= 286 -6

Step 5: Divide 4 on both sides.
4x/4 = 280/4

x=70

Which means the answer is 70, 71, 72, 73

Check Work:
70+71+72+73= 286

So this is correct :)

3 0

3 years ago

Which expression is equivalent to (7^3)^-2? (4 points)<br> 1/7^6<br> 7<br> 1/7<br> -1/7^6

murzikaleks [220]

Answer:

d

Step-by-step explanation:

7 0

3 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0

1 year ago

There were 196 students that participated in a clean-up event at a nearby lake. this is one fourth of the entire student populat

Norma-Jean [14]

Hello there.

<span>There were 196 students that participated in a clean-up event at a nearby lake. this is one fourth of the entire student population. write and solve an equation to find the number of students at this school.

Answer: x is the number of students in the school.
</span> $\frac{x}{4}$ = 196.
<span>196 x 4 = 784.
Therefore the number of students in this school is 784.

Hope This Helps You!
Good Luck Studying ^-^</span>

6 0

3 years ago