Researchers asked 250 families whether or not they were homeowners and how many cars they had. Their responses are summarized in
the following table.
No car or one car Two or more cars
Homeowner
25
90
Not a homeowner
45
90
(a) what percentage of the families are homeowners?
(b) What percentage of the familles have two or more cars?
х
S
?
(b) 1%
Explanation
Check
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No car or one car Two or more cars
Homeowner
25
90
Not a homeowner
45
90
(a) what percentage of the families are homeowners?
(b) What percentage of the familles have two or more cars?
х
S
?
(b) 1%
Explanation
Check
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1 answer:
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Answer:
V(X)= 39.10
V(Y)= 40
Step-by-step explanation:
Given that
Total number of student = 140
Bus A - 31
Bus B- 43
Bus C- 27
Bus D- 39
The probability that a student was on the bus is proportional to the number of student. Eg 31/140 in bus A, 43/140 on bus B, ...
E(X) = (31*31/140) + (43*43/140) + (27*27/140) + (39*39/140)
= 35.5
V(X)= 39.10
The bus driver have 1/4 probability on being on any of the buses.
E(Y) = 140/4 = 35
V(Y)= 40