0.008 i think this is the answer
Answer:
0.128
Step-by-step explanation:
We know the probability for any event X is given by,
,
where p is the probability of success and q is the probability of failure.
Here, we are given that p = 0.533.
Since, we have that q = 1 - p
i.e. q = 1 - 0.533
i.e. q = 0.467
It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.
Substituting the values in the above formula, we get,
i.e. 
i.e.
i.e. i.e. 
Hence, the probability of 4 wins in the next 5 games is 0.128.
f(x) = 4x + 3
That's one-to-one, a linear function that will give a different f(x) for each different x.
For the inverse let's swap x and y and solve for y
x = 4y + 3
x - 3 = 4y
y = (x- 3)/4
That's the inverse,
Answer: (x- 3)/4, second choice
The domain and range of the inverse is all real numbers. It's two lines; I'll leave the graphing to you.
We have to find the value of x from the given equation.
- (x - 2)(x² - 2x + 2) = 0 is a quadratic equation, so it will have two values.
Step: Write the equation in simplest form.
Step: Solve the problem by spiltting method.
- (x-2)(x² - x -x + 1) = 0
- (x - 2)(x²-x - x + 1) = 0
- (x - 2) [x(x - 1) -1(x -1)]
- (x - 2)[(x-1)(x-1)]
Step: Solve the problem with using algebraic formula.
{x-1](x-1)
Step : We have used a²-b² to solve the problem.
(x-2)(x² - x -x + 1) = 0
(x - 2)(x²-x - x + 1) = 0
(x - 2) [x(x - 1) -1(x -1)]
(x - 2)[(x-1)(x-1)]
Therefore, the possible factorization is (x - 2)[(x-1)(x-1)].
