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Sphinxa [80]
3 years ago
11

6.SP.2 Understand that a set of data collected to answer a statistical question has a distribution which can be described by its

Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0
Probably
If you didn’t know my brush the pool
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Are the answers for 1-3 correct? I need help with 4 and 5!!! Please!
vovangra [49]
1.

a. 12d² -6d

b. 6c^5 + 8c^4 -10c³

c. correct

2. 

a. correct

b. correct

c. 12r^8-6r^4 + 9r^2, then multiply the rest by -1

3. correct

4. x² + 10

5. d=4, -1/3
8 0
3 years ago
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Factor completely 5a2 + b.<br><br> Prime<br><br> a(5a + b)<br><br> b(5a2)<br><br> ab(5a + 1)
Tatiana [17]
\sf {5a^2+b~is~\boxed{\bf{prime}}}

It is prime because it has no common factors in 5a^2 and b.

The answer is A<span>.</span>
6 0
3 years ago
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How many solutions does this system of linear equations have? Explain. 3y + 6x = 12 8x + 4y = 16
Vilka [71]

Answer:

first equation : 3y + 6×=12

second equation : 4y + 8x = 16

Step-by-step explanation:

first equation

3y + 6× = 12

now take the common ,

3( y + 2x ) = 12

so, y + 2x = 4

second equation

4y + 8x = 16

4 ( y + 2x ) = 16

so, y + 2x = 4

two lines with same equation have infinitely many solution . these two equations are the same so there are infinitely many solution .

3 0
3 years ago
Lifetime of $1 Bills The average lifetime of circulated $1 bills is 18 months. A researcher believes that the average lifetime i
OLEGan [10]
<h2>Answer with explanation:</h2>

Let \mu be the population mean lifetime of circulated $1 bills.

By considering the given information , we have :-

H_0:\mu=18\\\\H_a:\mu\neq18

Since the alternative hypotheses is two tailed so the test is a two tailed test.

We assume that the lifetime of circulated $1 bills is normally distributed.

Given : Sample size :  n=50 , which is greater than 30 .

It means the sample is large so we use z-test.

Sample mean : \overline{x}=18.8

Standard deviation : \sigma=2.8

Test statistic for population mean :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{18.8-18}{\dfrac{2.8}{\sqrt{50}}}\approx2.02

The p-value= 2P(z>2.02)=0.0433834

Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.

6 0
3 years ago
Find the volume of a cylinder with height 14.7 cm and diameter 10.5 cm.
velikii [3]

Hello!

The volume of a cylinder is found by using the formula: V = πr²h.

The problem has given us the height of the cylinder, which is 14.7 centimeters, and the diameter which is 10.5 centimeters. The volume of a cylinder requires the radius, so therefore, to find the radius, divide the diameter by half, and that will give the radius.

R = 10.5 / 2

R = 5.25 centimeters

With that radius and the height, we can find the volume of the cylinder.

V = π(5.25)²(14.7)

V = 27.5625(14.7)π

V = 405.17π, 1272.23 (multiplied by 3.14), 1272.88 (multiplied by π)

Therefore, the volume of this cylinder is 1272.88 centimeters³.

5 0
3 years ago
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