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3 years ago

Please help me. Please.

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

7 0

8,3 is QI
9,-2 is QIV
-3.5,-6 is QIII

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36" = _____° 0.01 0.10 0.50 0.60

Tresset [83]

Answer:

.01

Step-by-step explanation:

There are 3600'' in 1°. 36"/3600"= .01°

6 0

3 years ago

Which shows the correct solution to the inequality 7/10> 1 5/8+p

Bogdan [553]

Answer: $\begin{bmatrix}\mathrm{Solution:}\:&\:p$

Step-by-step explanation:

$\frac{7}{10}>1\frac{5}{8}+p$

$\frac{7}{10}>\frac{13}{8}+p$

$\frac{13}{8}+p$

$\frac{13}{8}+p-\frac{13}{8}$

$p$

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3 years ago

Find the sum of 997 + 992 + 987 +...+ 257 +252

Vikentia [17]

Answer:

93,675

Step-by-step explanation:

We see that the given sequence is an arithmetic sequence with first term 997, common difference -5, and last term 252.

The number of terms in the sequence (n) can be found from the formula for the n-th term:

an = a1 +d(n -1)

(an -an)/d +1 = n

(252 -997)/(-5) +1 = n = 150

The sum of these terms is the average of the first and last terms, multiplied by the number of terms:

S150 = (997 +252)/2·150 = 93,675

The sequence sum is 93,675.

7 0

3 years ago

What is the slope of the line through (-1, -7) and (3,9)?

Radda [10]

Answer:

9+7

3+1

Step-by-step explanation:

5 0

2 years ago

What is the 6th term of the geometric sequence where a1 = 1,024 and a4 = −16? 1 −0.25 −1 0.25

VLD [36.1K]

The n-th term is given by

$a_n=a_1\cdot r^{(n-1)}\qquad\text{where r is the common ratio}$

Then we can find the common ratio from the given terms.

$\dfrac{a_4}{a_1}=\dfrac{a_1\cdot r^{(4-1)}}{a_1}=r^3=\dfrac{-16}{1024}=\left(\dfrac{-1}{4}\right)^3\\\\r=\dfrac{-1}{4}\\\\a_6=1024\left(\dfrac{-1}{4}\right)^5=-1$

The appropriate choice is -1.

8 0

3 years ago

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