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Brums [2.3K]
3 years ago
15

Please help me. Please.

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0
8,3 is QI
9,-2 is QIV
-3.5,-6 is QIII
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The first steps in writing f(x) = 3x^2 -24x+10 in vertex form what is the function written in vertex form
Vika [28.1K]
F(x) = 3(x-4)^2-38 because finding the perfect square would get you f(x)+38=3(x^2-8x+16) and then finding the squareroot of that and moving the constant on the left back to the right would leave u with f(x)=3(x-4)^2-38
4 0
3 years ago
Read 2 more answers
dollars of a Class party is 59 + 13 in where in is the number of people attending what is the cost for 44 people
Alina [70]
Plug in 44
so
59+13(44) = 631
7 0
4 years ago
The vertex of the parabola below is at the point (3,2) and the point (4,6) is on the parabola. What is the equation of the parab
nata0808 [166]

Answer:

\large\boxed{y=4(x-3)^2+2\ \bold{vertex\ form}}\\\boxed{y=4x^2-24x+38\ \bold{standard\ form}}

Step-by-step explanation:

The vertex form of a parabola:

y=a(x-h)^2+k

(h, k) - vertex

We have the vertex at (3, 2) → h = 3 and k = 2.

Substitute:

y=a(x-3)^2+2

The point (4, 6) is on athe parabola. Put the coordinates of this point to the equation:

6=a(4-3)^2+2       <em>subtract 2 from both sides</em>

6-2=a(1)^2+2-2

4=a\to a=4

Finally:

y=4(x-3)^2+2          <em>vertex form</em>

<em>use (a - b)² = a² - 2ab + b²</em>

y=4(x^2-6x+9)+2          <em>use the distributive property</em>

y=4x^2-24x+36+2

y=4x^2-24x+38             <em>standard form</em>

6 0
3 years ago
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS
77julia77 [94]

Here is the answer sis lol

5 0
2 years ago
Using the functions s = 13.5h, which statement is true?
Archy [21]

A function is a relationship between inputs where each input is related to exactly one output.

The domain of s = 13.5h are (0, 1, 2, 3, 4).

The range of s = 13.5h are (0, 13.5, 27, 40.5, 54).

<h3>What is a function?</h3>

A function is a relationship between inputs where each input is related to exactly one output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

s = 13.5h

For h = 0,

s = 0

For h = 1,

s = 13.5

For h = 2,

s = 27

For h = 3,

s = 40.5

For h = 4,

s = 54

We see that,

The domain of s = 13.5h are (0, 1, 2, 3, 4).

The range of s = 13.5h are (0, 13.5, 27, 40.5, 54).

Thus,

The domain of s = 13.5h are (0, 1, 2, 3, 4).

The range of s = 13.5h are (0, 13.5, 27, 40.5,  54).

Learn more about functions here:

brainly.com/question/28533782

#SPJ1

3 0
1 year ago
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