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3 years ago

6

Using the circle below, determine the coordinates of the center and the length of the radius

1 answer:

lidiya [134]3 years ago

5 0

(3,2) is the center and the radius is 2. You can see this by taking where the dot is in the graph (in this case (3,2)) that is your middle, while the radius is one half of the circle, basically how many points are between the circle and the dot. Hope this helps!

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What’s the answer please??

vodomira [7]

Answer: C

Step-by-step explanation:

7 0

3 years ago

How to graph {3x-8y = 29

labwork [276]

<span>How to graph {3x-8y = 29 3x+y = -2}
</span> The first thing you should do is to clear "y". Then, you must substitute values of x in the equation to find the values of "y". Finally, graph the points obtained. (see graphic)
How do you convert this to slope intercept form? 3x-8y = 29 ---> y = 0.375x - 3.625 3x+y = -2 ---> y = -3x - 2

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3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

Use the pythagorean theorem 1) a=7 b=12

steposvetlana [31]

Answer:

√193

Step-by-step explanation:

7^2 = 49

12^2 = 144

144 + 49= 193

√193 because you are trying to find c not c^2

5 0

2 years ago

Given the coordinates for the function below which of the following are coordinates for its inverse

IgorLugansk [536]

Answer:

Not sure but I believe it is A

Step-by-step explanation:

7 0

3 years ago