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iogann1982 [59]
3 years ago
10

Find four consecutive integers such that 5 times the fourth diminished by twice the second is 7

Mathematics
1 answer:
Lynna [10]3 years ago
7 0

Answer:

-2, -1, 0, 1

Step-by-step explanation:

Let the 4 numbers be x,x+1, x+2, x+3

Then we have the equation:-

5(x+3)-2(x+1) = 7

5x - 2x + 15 - 2 = 7

3x = - 6

x = -2


so the integers are  -2, -1, 0, 1

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Read 2 more answers
Jika sin x = p, dengan x tumpul, maka cos(x + 60) =​
Novay_Z [31]

Menjawab:

[(√1-p²) -3√p] / 2

Penjelasan langkah demi langkah:

Dari identitas trigonometri, pemuaiannya benar:

Cos (A + B) = cosAcosB-sinAsinB

Menerapkan ini dalam memperluas cos (x + 60).

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Jika sinx = p = berlawanan / sisi miring

opp = p, hyp = 1

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Cos (x) = √1-p²

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Mengganti nilai-nilai ini ke dalam rumus

cos (x + 60) = cosxcos60 - sinxsin60

cos (x + 60) = √1-p² (1/2) - p (√3 / 2)

cos (x + 60) = (√1-p²) / 2 - √3p / 2

Temukan KPK tersebut

cos (x + 60) = [(√1-p²) -3√p] / 2

Oleh karena itu cos (x + 60) = [(√1-p²) -3√p] / 2

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