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3 years ago

Find four consecutive integers such that 5 times the fourth diminished by twice the second is 7

Mathematics

1 answer:

Lynna [10]3 years ago

7 0

Answer:

-2, -1, 0, 1

Step-by-step explanation:

Let the 4 numbers be x,x+1, x+2, x+3

Then we have the equation:-

5(x+3)-2(x+1) = 7

5x - 2x + 15 - 2 = 7

3x = - 6

x = -2

so the integers are -2, -1, 0, 1

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