OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Well first you times the 0.3 to w and 10 which will give you 0.3w + 3 = 1.8w and subtracting 1.8 from 0.3 gives you
1.5w=3 and that is divided to w=2
F(x+1) = (x + 1)^3
= 3x + 3
= 3(0) + 3
= 3
I think is 3
Answer: 10
Explanation: you need to first find the area of the triangle which would be 2x2x1/2 then you find the area of the rectangle which is 4x2 so 8+2=10
