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navik [9.2K]
3 years ago
7

What is the formula for a finite geometric series and how can use it in a practical situation

Mathematics
1 answer:
Soloha48 [4]3 years ago
5 0

The sum S_{n} of n terms of a geometric series with first term a_{1} and common ratio r is given by

S_{n}=a_{1}\cdot \dfrac{r^{n}-1}{r-1}

It can be used in any situation involving the accumulated consequences of exponential growth. In finance, it is used to find the future value of a sequence of payments subject to compound interest.

For example, consider 10 deposits of 1000 made at the end of the year into an account paying 2% compounded annually. The result of such a sequence of payments will be

S_{10}=\$1000\cdot \dfrac{1.02^{10}-1}{1.02-1}=\$10,949.72

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If the area of a square is 125 square meters, estimate the length of each side of the square to the nearest integer.
Afina-wow [57]

Answer:

11

Step-by-step explanation:

area of a square is x²

we have x² = 125

x = √(25×5)

x =5√5

x = 11.180

x ~ 11

5 0
3 years ago
What is (5-4b) (3-8b)
tester [92]
15-40b-12b+32b^2 so your final answer in standard form would be 32b^2-52b+15
5 0
3 years ago
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Payton starts a lemonade stand for the summer. She thinks that she should be able to operate her business for 14 weeks. The tabl
kotykmax [81]

Answer:

Payton starts a lemonade stand for the summer. She thinks that she should be able to operate her business for 14 weeks. The table shows the

expenses and revenue after 1 week.

Item

Expenses Revenue

$5

Cups

Lemonade

$6

$7

Ice

Income

$45

Based on this, how much money will Payton make during the 14 weeks?

8 0
3 years ago
X - 4y - 1 = 0<br> x + 5y - 4 = 0<br><br> solve for comparison
KIM [24]
x-4y-1=0
-x-5y-4=0
----------------
0+y+3=0
y+3-3=0-3
y=-3

Substituting y=-3 in the equation x-4y-1=0
x-4×-3-1=0
x+12-1=0
x+11-11=0-11
x=-11


8 0
3 years ago
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Divide and simplify.
vredina [299]

Answer:

\frac{ {x}^{2} + 10x + 16 }{ {x }  {}^{2}  + 6x + 8} \div  \frac{1}{x + 2}

\frac{ {x}^{2} + 8 x+  2x + 16}{ {x}^{2}  + 4x + 2x + 8}  \times (x + 2)

\frac{x(x + 8) + 2 (x + 8)}{x(x + 4) + 2(x + 4)}  \times (x + 2)

\frac{( x + 8)(x + 2)}{(x + 2)(x + 4)}  \times ( x + 2)

\frac{( x + 8)(x + 2)}{(x + 4)}

3 0
3 years ago
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