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34kurt
3 years ago
5

PLEASE HELP!!!!!!!!!!!! WILL MARK BAINLIEST!

Mathematics
1 answer:
Mila [183]3 years ago
6 0

Answer:

i’m like 60% sure it’s a

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Which expression is equivalent to m^2-13m-30?
sergiy2304 [10]

Answer: First option

Step-by-step explanation:

You have the quadratic equation given in the problem:

m^2-13m-30

To find an equivalent expression you cacn factorize. Find two numbers whose sum is -13 and whose product is -30.

These numbers would be -15 and 2.

Therfore, you obtain the following equivalent expression:

(m-15)(m+2)

If you don't want to apply the method above, you can use the quadratic formula:

x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}

Where:

a=1\\b=-13\\c=-30

When you susbstitute values you obtain that:

x=15\\x=-2

Then you can rewrite the equation as (m-15)(m+2)

7 0
3 years ago
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On Monday, the Dairy Barn sold 14 waffle cones for every 6 sugar cones. On Tuesday, the Dairy Barn sold 7 waffle cones for every
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Answer:

Option b

Step-by-step explanation:

To represent this proportion using fractions, let the numerators be the number of waffles sold and denominator, the number of sugar cones.

Thus, the proportion that can be used to represent the cone sales is

14/6 = 7/3

3 0
3 years ago
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3a-3/a+6=9/6 what is a
Gekata [30.6K]

Answer:

a=1/2

Step-by-step explanation:

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Find the length of c
tino4ka555 [31]
16 is the correct answer
5 0
3 years ago
To better understand the financial burden students are faced with each term, the statistics department would like to know how mu
Semmy [17]

Answer:

Answer:

a).

The amount spent on school materials for each term of all ST201students

b).

a).

It is not a random sample. This looks like a convenience sampling and there is sampling bias. This sample is not representative of the entire population. Since it is not a random sample it is not appropriate to generalize the results to all students.

b).

The sample size is 80 which is greater than 30. It is large enough to assume normal distribution according to central limit theorem.

c).

mean: $617

z critical value at 95%: 1.96

standard error = σ/sqrt(n) =500/sqrt(80) = 55.9017

lower limit= mean-1.96*se = 617-1.96*55.9017=507.43

upper limit= mean+1.96*se = 617+1.96*55.9017=726.57

d).

The amount spent on school materials for each term for the 80 ST201students is $617. We are 95% confident that amount spent on school materials for each term of all ST201students falls in the interval ($507.43, $726.57).

Step-by-step explanation:

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