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Kay [80]
3 years ago
13

Which expression can be used to determine the length of segment AB?

Mathematics
1 answer:
Studentka2010 [4]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Calculate the length using the distance formula

AB = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(4,3) and (x₂, y₂ ) = B(- 2, 1)

AB = \sqrt{(-2-4)^2+(1-3)^2}

     = \sqrt{(-6)^2+(-2)^2}

     = \sqrt{36+4}

     = \sqrt{40}

     = \sqrt{4(10)} = \sqrt{4} × \sqrt{10} = 2\sqrt{10} ← exact length

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Answer:

{x = 1, y = -5

Step-by-step explanation:

Solve the following system:

{-3 x - 3 y = 12 | (equation 1)

{3 y - 9 x = -24 | (equation 2)

Swap equation 1 with equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

{-(3 x) - 3 y = 12 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

0 x - 4 y = 20 | (equation 2)

Divide equation 1 by 3:

{-(3 x) + y = -8 | (equation 1)

{0 x - 4 y = 20 | (equation 2)

Divide equation 2 by 4:

{-(3 x) + y = -8 | (equation 1)

{0 x - y = 5 | (equation 2)

Multiply equation 2 by -1:

{-(3 x) + y = -8 | (equation 1)

{0 x+y = -5 | (equation 2)

Subtract equation 2 from equation 1:

{-(3 x)+0 y = -3 | (equation 1)

{0 x+y = -5 | (equation 2)

Divide equation 1 by -3:

{x+0 y = 1 | (equation 1)

{0 x+y = -5 | (equation 2)

Collect results:

Answer:  {x = 1 , y = -5

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