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vfiekz [6]
3 years ago
5

For the following right triangle, find the side length x

Mathematics
2 answers:
Aleks [24]3 years ago
7 0

Answer:

x = 25

Step-by-step explanation:

b² + h² = x²

24² + 7² = x²

576 + 49 = x²

625 = x²

√625 = √x²

25 = x

alexdok [17]3 years ago
3 0

Step-by-step explanation:

x² = 7² + 24²

x² = 49 + 576

x² = 625

x = 25

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Solve the Anti derivative.​
Alex Ar [27]

Answer:

\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C

General Formulas and Concepts:

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]:                                                                \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Trig Integration:                                                                                                           \displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx<u />

<u />

<u>Step 2: Integrate Pt. 1</u>

  1. [Integral] Factor fraction denominator:                                                         \displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx
  2. [Integral] Integration Property - Multiplied Constant:                                   \displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx

<u>Step 3: Identify Variables</u>

<em>Set up u-substitution for the arctan trig integration.</em>

\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx

<u>Step 4: Integrate Pt. 2</u>

  1. [Integral] Substitute u-du:                                                                               \displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du
  2. [Integral] Trig Integration:                                                                               \displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C
  3. [Integral] Simplify:                                                                                           \displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C
  4. [integral] Multiply:                                                                                           \displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C
  5. [Integral] Back-Substitute:                                                                             \displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0
3 years ago
What is the area of the sector of the circle below, if the radius is 5 m. and the central angle &lt; AOB measures 88 °. (round a
MariettaO [177]

Answer:

b 19.2

Step-by-step explanation:

a = \pir^{2} for a circle.  We do not want to find the area for a whole circle.  We only want to find the area for part of a circle.  a hole circle is 360 degrees.

a = \frac{88}{360}\pir^{2}

a = \frac{88}{360}\pi(5^{2})

a = 19.2 rounded.

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Nataly [62]
Answer = $160

Using the formula 100+4n, we need to substitute 15 with n. Therefore making the formula, 100 + 4×15. 4×15 = 60. 60+100= $160.

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Step-by-step explanation:

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x = 4.5 hours

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