Answer:
The two equations that can be used to find each of their ages are
and
.
Step-by-step explanation:
We are given that Mrs. Lang is 4 times as old as her daughter Jill. The sum of their ages is 60 years.
Let the age of Mrs. Lang be 'x years' and the age of her daughter Jill be 'y years'.
Now, according to the question;
- The <u>first condition</u> states that Mrs. Lang is 4 times as old as her daughter Jill, that means;
----------------- [equation 1]
- The <u>second condition</u> states that the sum of their ages is 60 years, that means;
{using equation 1}

y = 12 years
Now, putting the value of y in equation 1 we get;
= 48 years
Hence, the age of Mrs. Lang is 48 years and her daughter Jill is 12 years old.
24/25 in fraction and simplest form. Hope this helps!
A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit
"The sum of the digits is 5"
x + y = 5
The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]
The number is: 10x + y
3(10x + y) = 42
The system of equations: (two equations for two unknowns)
x + y = 5
30x + 3y = 42
Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out
-3x - 3y = -15
30x + 3y = 42
------------------
27x + 0 = 27
x = 1
then plug x = 1 into either equation to find y
1 + y = 5
y = 4
remember the x and y represent digits so the number xy is 14
Answer:
<em>$11.21</em>
Step-by-step explanation:
$30.00 - $18.79 = $11.21