I don’t have enough information to answer your question.
The surface area of the pyramid will be given as follows:
Area of triangles:
A=1/2×base×height
A=1/2×12×18
A=108 m²
Area of 6 triangles is given by:
A=108×6=648 m²
Area of the hexagon:
A=6×1/2×12×6√3
A=374.123m²
Total surface area:
SA=648+374.123
SA=1022.123 m²~1022 m²
Answer: C] 1022 m²
Do you have any more information???
11/21 would be the answer
If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
