The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
Order of operations (from high priority to low priority):
Parentheses
Exponents
Multiplications/Division
Addition/Subtraction
All in left to right.
2 ÷ (5 + 3)⁻¹ ÷ 4
2 ÷ (8)⁻¹ ÷ 4
2 ÷ 1/8 ÷ 4
16 ÷ 4
= 4
