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3 years ago

Cole made a scale drawing of the elementary school. The scale he used was

Mathematics

1 answer:

ahrayia [7]3 years ago

3 0

Answer:

I think 60

Step-by-step explanation:

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Can someone please answer these questions?

Arisa [49]

Keep in mind that you can gather only like terms. Two terms can be summed/subtracted if they involve the same powers of the same variables.

So, going point by point:

We can subtract the terms, because they both involve the variable $b$ , and we have $3b-7b = (3-7)b = -4b$
We can sum the terms, because they all involve the variable $a$ , and we have $a+a-5a = (1+1-5)a = -3a$
We can't sum this terms: 3 is a pure number, while 3r involves the variable r.
We can only sum the two terms: we have $7t-8t-8 = (7-8)t-8 = -t-8$
We can't sum this terms: -20 is a pure number, while -15p involves the variable p.
We can sum the terms, because they all involve the variable $g$ , and we have $-g-g-g = (-1-1-1)g = -3g$

7 0

3 years ago

HELP ME!!! Answer in Scientific Notation and explain and show work.

umka21 [38]

Multiplying means you add the exponents and dividing means you subtract the exponents. Treat the decimals as you normally would.
$(4.3 \times {10}^{8} ) \times (2.0 \times {10}^{6} )$
$4.3 \times 2.0 = 8.6$
$8 + 6 = 14$
$8.6 \times {10}^{14}$

$(6 \times {10}^{3} ) \times (1.5 \times {10}^{ - 2} )$
$6 \times 1.5 = 9$
$3 + - 2 = 1$
$9 \times {10}^{1}$

$(1.5 \times {10}^{ - 2} ) \times (8.0 \times {10}^{ - 1} )$
$1.5 \times 8 = 12$
$- 2 + - 1 = - 3$
$12 \times {10}^{ - 3}$

$\frac{(7.8 \times {10}^{3}) }{(1.2 \times {10}^{4}) }$
$\frac{7.8}{1.2} = 6.5$
$3 - 4 = - 1$
$6.5 \times {10}^{ - 1}$

$\frac{(8.1 \times {10}^{ - 2} )}{(9.0 \times {10}^{2} )}$
$\frac{8.1}{9.0} = 0.9$
$- 2 - 2 = - 4$
$0.9 \times {10}^{ - 4}$

$\frac{6.48 \times {10}^{5} }{(2.4 \times {10}^{4} )(1.8 \times {10}^{ - 2}) }$
$2.4 \times 1.8 = 4.32$
$4 + - 2 = 2$
$\frac{6.48 \times {10}^{5} }{4.32 \times {10}^{2} }$
$\frac{6.48}{4.32} = 1.5$
$5 - 2 = 3$
$1.5 \times {10}^{3}$

7 0

3 years ago

A and B share the cost in a ratio of 3:2 A pays 125£ how much does b pay???

lana66690 [7]

Let the common multiple be x
3x : 2x 
3x = 125 
x = 125/3 

So, B pays 2x = 2 × 125/3 = £250/3

8 0

3 years ago

Read 2 more answers

Hans rented a truck for one day. there was a base fee of $16.99 , and there was an additional charge of 75 cents for each mile d

SSSSS [86.1K]

186 miles, Hans drove to reach $139

8 0