3^2*3^2 (2x+3)=3^2+4x+6=3^4x+8
3^3*3^x-2=3^x+1
4x+8=x+1
3x=-7
x=-7/3
A=h7
divide both sides by h
A\7=h
Answer:
C. 
General Formulas and Concepts:
<u>Calculus</u>
- Mean Value Theorem (MVT) - If f is continuous on interval [a, b], then there is a c∈[a, b] such that

- MVT is also Average Value
Step-by-step explanation:
<u>Step 1: Define</u>

f'(c) = 20
Interval [1, b]
<u>Step 2: Check/Identify</u>
Function [1, b] is continuous.
Derivative [1, b] is continuous.
∴ There exists a c∈[1, b] such that 
<u>Step 3: Mean Value Theorem</u>
- Substitute:

- Rewrite:

And we have our final answer!
<h3>
Answer: I can't draw on this though</h3>
Step-by-step explanation: