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4 years ago

(PLEASE HELP MATH QUESTION

Mathematics

1 answer:

saveliy_v [14]4 years ago

6 0

I believe the answer you want is the third option

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For every 3 wrapped packages Mary uses 1/2 roll of wrapping paper how many packages can she wrap with 2 1/2 rolls of wrapping pa

grin007 [14]

She can wrap 15 packages :)

6 0

3 years ago

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A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago

Hello, can anyone help please? :D

Lubov Fominskaja [6]

Answer:

just guess

Step-by-step explanation:

i got it right

6 0

3 years ago

Find the area of the isosceles triangle. please help thanks

fiasKO [112]

Answer:

1080 m^2 Don't submit m^2 in your answer.

Step-by-step explanation:

Givens

The catch is to find h

To do that, use a^2 + b^2 = c^2

a b and c are in the same 1/2 triangle.

a = 48/2 = 24 m

b = h = ?

c = 51 meters

Solution

a^2 + b^2 = 51^2 Substitute for b^2 = h^2

24^2 + h^2 = 51^2 Expand 24^2 and 51^2

576 + h^2 = 2601 Subtract 576 from both sides

h^2 = 2601 - 576

h^2 = 2025 Take the square root of both sides

h = 45

Area

Area = 1/2 b * h

Area = 1/2 48 * 45

Area = 1080

Remark

Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.

To find the area, you need to use all of 48 because 48 is the full length of the base.

5 0

3 years ago

Please help and make it right..

Readme [11.4K]

Answer:

2.67 and 4.67 I think .........

8 0

3 years ago

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