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notka56 [123]
3 years ago
15

Find x and y if x=2y-8 and y=9x-7

Mathematics
1 answer:
german3 years ago
6 0

Answer:

x = (22/17), y= (79/17)

Step-by-step explanation:

Just substitute x = 2y - 8 into y = 9x - 7 and solve.

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Please help with this math question
nika2105 [10]
263.27 m^2

rectangle : 15 x 10 = 150 m^2
the half circle at the top has a diameter of 6m. therefore, it’s radius is 3m. if it is cut in half, the part removed from the triangle height is 3m. therefore, the height of the triangle is 35 -15 = 20; 20 - 3 = 17. the height of the triangle is 17. the triangle area formula is a = 1/2(bh).
a = 1/2 (10)(17)
a = 1/2 (170)
a = 85 m^2
the circle would be a = πr^2 but divided by 2 bc it’s a half circle
a = π(3)^2
a = π9
a = 28.27 m^2
150 + 85 + 28.27 = 263.27 m^2
3 0
3 years ago
Suppose you write a system of equations to find out which of two video stores is cheaper to join, depending on the number of vid
SCORPION-xisa [38]
The right answer is c
6 0
3 years ago
Find the slope of the line that passes through (-34, 72) and (31, 27).
ZanzabumX [31]
The answer i got is -9/13
8 0
3 years ago
Read 2 more answers
-8(8v + 1) - 2 = -394
Bess [88]

Answer:

v = 6

Step-by-step explanation:

Solve for v:

-8 (8 v + 1) - 2 = -394

-8 (8 v + 1) = -64 v - 8:

-64 v - 8 - 2 = -394

Grouping like terms, -64 v - 8 - 2 = -64 v + (-8 - 2):

-64 v + (-8 - 2) = -394

-8 - 2 = -10:

-10 - 64 v = -394

Add 10 to both sides:

(10 - 10) - 64 v = 10 - 394

10 - 10 = 0:

-64 v = 10 - 394

10 - 394 = -384:

-64 v = -384

Divide both sides of -64 v = -384 by -64:

(-64 v)/(-64) = (-384)/(-64)

(-64)/(-64) = 1:

v = (-384)/(-64)

The gcd of -384 and -64 is -64, so (-384)/(-64) = (-64×6)/(-64×1) = (-64)/(-64)×6 = 6:

Answer:  v = 6

3 0
3 years ago
Read 2 more answers
Which is the sum of 3/10 and 1/3
Ilya [14]

Step-by-step explanation:

\:  \:  \:  \:  \: \frac{3}{10}  +  \frac{1}{3}  \\  \\  =  \frac{3 \times 3}{10 \times 3}  +  \frac{1 \times 10}{3 \times 10}  \\  \\  =  \frac{9}{30}  +  \frac{10}{30}  \\ \\   =  \frac{19}{30}  \\  \\ so \: as \: you \: see \: here \: we \: should \: put \: same \: denominator \\ \: for \: both \: fractions. \: hope \: this \: helps.. \\ good \: luck

8 0
3 years ago
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