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VikaD [51]
3 years ago
7

Helpppp!!!! asap please and thank you

Mathematics
2 answers:
Alex73 [517]3 years ago
5 0

Answer:

11

Step-by-step explanation:

79 + 90 = 169

180 - 169 = 11

prisoha [69]3 years ago
4 0

Answer:

x=11°

Step-by-step explanation:

180-90-79=11

Hope this helps!

Please mark me brainliest if you can. :)

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Which system of inequalities is represented by the graph? <br> PLEASE HELP QUICK
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I put letter C for my answer
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Find sin A, cos A, tan A,
Vsevolod [243]

Answer:

Sin A= 24/30 Cos A = 18/30 Tan A =24/18

Step-by-step explanation:

This is because Sin is equal to opposite over hypotenuse. Cos is equal to adjacent over hypotenuse and Tan is equal to opposite over adjacent.

6 0
3 years ago
Sixty out of every 100 pieces of candy is red. Which Indicates the
JulsSmile [24]

Answer:

The proportion of red candies is 60/100.

Step-by-step explanation:

Given that sixty out of every 100 pieces of candy is red, to determine which indicates the proportion of red candies, the following calculation must be performed:

60 red candies out of 100 total candies

60/100

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8 0
3 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
Evaluate each expression for the given value of the variable <br> x-3/10 for x=1/2
faltersainse [42]

x-3/10 for x=1/2

1/2-3/10

=2/10

=1/5

3 0
4 years ago
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