Answer:
The answer is 65.75
Step-by-step explanation:
Since tq is perpendicular to PR then qtsr becomes square
Then

Since the triangle pqt is right angled
Then

Then the height of the pole is equal to

You can conclude that AE = DE because the triangles are about equal
Answer:
in order to find the area, we should break up the figure. you can see that in the image we have a quarter of a circle and a square. here are the areas for each of these shapes
square:

circle:

but since we only have a quarter of this circle we need to divide the area by 4 so the formula becomes

now we can plug in our numbers
we are given 6 m for our radius or length of square
the square will be (6)^2 = 36 m^2
now onto our circle
π(6)^2/4 = 28.26 m^2
now add these two shapes together to find the total area = 64.26 m^2
4y+5=-31 you subtract 5 from both sides so you get 4y=-36 then you divide by 4 from both sides so you get y=-9 and to check you put -9 in for y and multiply 4 and -9 add 5 to get -31