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SVEN [57.7K]
3 years ago
10

A phone company took a survey of its customers and found that 103 of 150 people said that they were pleased with their service t

he phone company has 72,000 customers what is w good predictions of the number of customers that are satisfied
Enter only the number of customers
Mathematics
2 answers:
Anarel [89]3 years ago
6 0
103 : 150
x : 72000

150x = 72000 \times 103 \\ 150x = 7416000 \\ x = 49440

Answer : Number of customers that are satisfied = 49,440

Hope this helps. - M
tino4ka555 [31]3 years ago
5 0
103 ÷ 150 = 0.68666666666

<span>0.68666666666 </span>× 72,000 = 49,440

Answer = 49,440

Hope this helped☺☺
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Step-by-step explanation:

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The scheduled commuting time on the Long Island Railroad from Glen Cove to New York City is 65 minutes. Suppose the actual commu
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3 years ago
What is the average rate of change of the function over the interval x = 0 to x = 8? f(x)=2x−1/3x+5 Enter your answer, as a frac
max2010maxim [7]

Answer:

15 2/3, or 47/3


Step-by-step explanation:

I'm going to assume, correctly or not, that you actually meant f(x) = 2x^2 - (1/3)x + 5.  Double check on this right now, please.

If I'm right, then evaluate f(x) at x = 0 and x = 8:

f(0) = 5

and

f(8) = 2(8)^2 - (1/3)(8) + 5 = 128 - 8/3 + 5 = 133  - (2 2/3), or:   130 1/3

Then the average rate of change of f(x) = 2x^2 - (1/3)x + 5 over the interval [0,8] is:

                130 1/3 - 5         125 1/3

a. r. c. = ------------------- = ---------------- = 15 2/3, or 47/3

                     8 - 0                  8

3 0
3 years ago
Jerry’s rhombus has a base of 15 inches and a height of 9 inches. Charlene’s rhombus has a base and a height that are 13 the bas
neonofarm [45]

Answer:  The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

Step-by-step explanation:

I will assume that the exercise says "\frac{1}{3} times the base and height of Jerry’s rhombus".

The area of a rhombus can be calculated with the following formula:

A=b*a

Where "b" is the length of the base  and "a" is the altitude or the height.

Then, you can calculate the area using the formula shown above.

Therefore, you get:

1. Jerry's rhombus:

A_1=(15\ in)(9\ in)\\\\A_1=135\ in^2

2. Charlene's rhombus:

A_2=(\frac{1}{3}*15\ in)(\frac{1}{3}*9\ in)\\\\A_2=(5\ in)(3\ in)\\\\A_2=15\ in^2

Dividing the area calculated, you get:

\frac{135\ in^2}{15\ in^2}=9

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

7 0
3 years ago
Read 2 more answers
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