Answer:
Step-by-step explanation:
The range is 10
Answer:
I think it is the 3rd one
Answer:
15 2/3, or 47/3
Step-by-step explanation:
I'm going to assume, correctly or not, that you actually meant f(x) = 2x^2 - (1/3)x + 5. Double check on this right now, please.
If I'm right, then evaluate f(x) at x = 0 and x = 8:
f(0) = 5
and
f(8) = 2(8)^2 - (1/3)(8) + 5 = 128 - 8/3 + 5 = 133 - (2 2/3), or: 130 1/3
Then the average rate of change of f(x) = 2x^2 - (1/3)x + 5 over the interval [0,8] is:
130 1/3 - 5 125 1/3
a. r. c. = ------------------- = ---------------- = 15 2/3, or 47/3
8 - 0 8
Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:

Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:

2. Charlene's rhombus:

Dividing the area calculated, you get:

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.