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maks197457 [2]
2 years ago
8

You have the same bowl, with 5 orange, 6 blue, 3 green, 4 red and 7 yellow candies. You take out an orange candy

Mathematics
1 answer:
siniylev [52]2 years ago
4 0

Answer:

A) 1/5

Step-by-step explanation:

There are 25 candies total, and you want to choose the 5 orange candies there.

That's 5/25.

Simplifying, we divide both sides by 5.

Thus, we get:

1/5.

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Tameron is driving 540
Ludmilka [50]

Do 540 ÷ 45 as you're first step. Then multiply that by 3/4.

540÷4= 12.

<h2><em>12 × 3/4 = 9.                       Awnser</em>: 9</h2>
6 0
2 years ago
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Help got to get this done ASP or I will not be able to test tommrow and I will get a F this is worth a 100 points so please help
Archy [21]
This is what I got. Good luck!

7 0
3 years ago
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Noelle has set a goal to run more than 50 mi this month. So far, she has run 10 mi. Her average running speed is 5 mph.
Vladimir79 [104]

Answer:

To meet her goal, Noelle must run more than 8\ hours the rest of the month

Step-by-step explanation:

Let

h-------> the number of hours Noelle runs for the rest of the month

we know that

The inequality that represent the situation is

10+5h>50

Solve for h

Subtract  10 both sides

5h> 50-10

5h> 40

Divide by 5 both sides

h> 8\ hours

3 0
3 years ago
ANSWER QUICKLY, ASSIGNMENT DUE AT 11:59! WORTH 100 POINTS
Brut [27]

f(2) is greater than g(2) and f(-2) is less than g(-2)

6 0
3 years ago
Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is
maw [93]

There are 120 ways in which 5  riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

Now,

Substituting values,

We get,

^5N_5 = \frac{5!}{(5-5)!}

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5  riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

#SPJ4

7 0
2 years ago
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