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Vlad [161]
3 years ago
11

Drag the labels to the correct locations. Each label can be used more than once, but not all labels will be used.

Mathematics
1 answer:
kupik [55]3 years ago
8 0

Answer:

x⁴ - 81 factors: x + 3, x - 3, x + 3i, x - 3i

x³ - 2x² + 9x - 18 factors: x - 3i, x + 3i, x - 2

x⁴ + 5x² - 36 factors: x - 2, x + 2, x + 3i, x - 3i

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Mama L [17]

Answer:

123.1 pounds is vary long, and I don't want to repeat, so 55.8372207 repeat.

Step-by-step explanation:

If you have any questions regarding my answer, tell me them in the comments, and I will come answer them for you. Have a good day.

8 0
2 years ago
How do I write c. Using if and then
pav-90 [236]
If half the sum of the bases is multiplied by the height, then that is the area of the trapezoid.
I believe this is the correct wording.

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5 0
3 years ago
Which of the following number is the smallest 0.1,0.01,0.001,0.0001​
atroni [7]

Answer:

0.0001

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If arc CE is 125°, what is the measure of angle CDE?
Delvig [45]

Check the picture below.

7 0
2 years ago
A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.
noname [10]

Answer:

Width = 4ft

Height = 4ft

Length = 8ft

Step-by-step explanation:

Given

Volume = 128ft^3

L = 2W

Base\ Cost = \$9/ft^2

Sides\ Cost = \$6/ft^2

Required

The dimension that minimizes the cost

The volume is:

Volume = LWH

This gives:

128 = LWH

Substitute L = 2W

128 = 2W * WH

128 = 2W^2H

Make H the subject

H = \frac{128}{2W^2}

H = \frac{64}{W^2}

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

A = LW + 2(WH + LH)

The cost is:

Cost = 9 * LW + 6 * 2(WH + LH)

Cost = 9 * LW + 12(WH + LH)

Cost = 9 * LW + 12H(W + L)

Substitute: H = \frac{64}{W^2} and L = 2W

Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)

Cost =18W^2 +  \frac{768}{W^2}*3W

Cost =18W^2 +  \frac{2304}{W}

To minimize the cost, we differentiate

C' =2*18W +  -1 * 2304W^{-2}

Then set to 0

2*18W +  -1 * 2304W^{-2} =0

36W - 2304W^{-2} =0

Rewrite as:

36W = 2304W^{-2}

Divide both sides by W

36 = 2304W^{-3}

Rewrite as:

36 = \frac{2304}{W^3}

Solve for W^3

W^3 = \frac{2304}{36}

W^3 = 64

Take cube roots

W = 4

Recall that:

L = 2W

L = 2 * 4

L = 8

H = \frac{64}{W^2}

H = \frac{64}{4^2}

H = \frac{64}{16}

H = 4

Hence, the dimension that minimizes the cost is:

Width = 4ft

Height = 4ft

Length = 8ft

8 0
3 years ago
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