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3 years ago

11

Drag the labels to the correct locations. Each label can be used more than once, but not all labels will be used.

1 answer:

kupik [55]3 years ago

8 0

Answer:

x⁴ - 81 factors: x + 3, x - 3, x + 3i, x - 3i

x³ - 2x² + 9x - 18 factors: x - 3i, x + 3i, x - 2

x⁴ + 5x² - 36 factors: x - 2, x + 2, x + 3i, x - 3i

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2. About how much is 123.1 do you weigh in pounds? Estimate if you don't know☺ Find an online converter and find out how many ki

Mama L [17]

Answer:

123.1 pounds is vary long, and I don't want to repeat, so 55.8372207 repeat.

Step-by-step explanation:

If you have any questions regarding my answer, tell me them in the comments, and I will come answer them for you. Have a good day.

8 0

2 years ago

How do I write c. Using if and then

pav-90 [236]

If half the sum of the bases is multiplied by the height, then that is the area of the trapezoid.
I believe this is the correct wording.

I am pretty sure these statements are created by taking the last part of the statement and pairing it with the “if” and the first part of the statement and pairing it with a “then” to make a complete statement.

I hope this helps! :)

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3 years ago

Which of the following number is the smallest 0.1,0.01,0.001,0.0001

atroni [7]

Answer:

0.0001

Step-by-step explanation:

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3 years ago

Read 2 more answers

If arc CE is 125°, what is the measure of angle CDE?

Delvig [45]

Check the picture below.

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2 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

3 years ago