Look at the first line: y = (3/5)x - 3. What happens if you multiply each term by 5, to eliminate the fraction?
5y = 3x - 3
Compare this to the second equation,
5y - 3x = -10, or 5y = 3x - 10.
The coefficients of x and y (as 3 and 5 here) determine the slope of a straight line. Since 5y = 3x is present in both equations, the two lines MUST be parallel.
y = 4
4y = 6 => y = 6/4
y+4 and y =3/2 are both horizontal lines. Since they are horiz., they are parallel.
Answer:
10 ft x 10 ft
Area = 100 ft^2
Step-by-step explanation:
Let 'S' be the length of the southern boundary fence and 'W' the length of the eastern and western sides of the fence.
The total area is given by:

The cost function is given by:

Replacing that relationship into the Area function and finding its derivate, we can find the value of 'S' for which the area is maximized when the derivate equals zero:

If S=10 then W =20 -10 = 10
Therefore, the largest area enclosed by the fence is:

Answer:
the MAD to this set is 6.75
Step-by-step explanation:
The process is pretty long on how to find the MAD but here it goes.First you find the mean of the set( 70 )then you find the distances between all the numbers and the mean( 68 is 2 values away from being 70 so that would be 2) than you add all the distances together than divide that number by the amount of values are in the set.
hope that makes sense have a good day
Answer:
0.505 g is <em>more than</em> the advertised amount by 0.005 g.
Step-by-step explanation:
0.5 = 0.500, so 0.505 is <em>more than</em> the advertised amount.
"Too little" or "too much" is a judgment based on some criteria not specified by the problem statement. Usually a supplier will want to ensure the customer receives full measure, so will adjust the capsule-making machine to provide at least the advertised amount. Whether it is "too little" or "too much" depends on your point of view and the dangers or costs of deviating from the advertised amount.
0.505 - 0.500 = 0.005 . . . . the difference between the actual and advertised amounts, in grams.