The probability of getting a total that is a factor of 21 is 0.22
<u>Explanation:</u>
Factor of 21 is = 1, 3, 7, 21
Out of all the factors of 21, we cannot get 21 when the two die are rolled as the maximum sum that can be obtained is 12
The possible combinations are:
(1,2) (1,6)
(2,1) (2,5)
(3,4)
(4,3)
(5,2)
(6,1)
Total outcome = 6 X 6
= 36
Number of outcomes that is the factor of 21 is 8
The probability of getting a total that is a factor of 21 is 
p(21) = 0.22
Therefore, the probability of getting a total that is a factor of 21 is 0.22
Answer:
a=8b
Step-by-step explanation:
To do this we just need to isolate a
so we can multiply the equation by b
then we will get
a=8b
If we are eliminating x, we would multiply the 2nd equation by -5
5x + 18y = 23
x + 3y = 2....multiply by -5
-----------------
5x + 18y = 23
-5x - 15y = - 10 (result of multiplying by -5)
----------------add
0 + 3y = 13.....bye-bye x :)
∑ 4 * 5^(i-1) = 4 + 20 + 100 + 500 = 624
∑ 3 * 4^(i-1) = 3 + 12 + 48 + 192 + 768 = 1,023
∑ 5* 6^(i-1) = 5 + 30 = 35
∑ 5^(i-1) = 1 + 5 + 25 + 125 = 156
Answer:
∑ (i=1, 2) 5 * 6^(i-1) < ∑ (i=1, 4) 5^(i-1) < ∑ (i=1, 4) 4 * 5^(i-1) <
< ∑ (i=1, 5) 3 * 4^(i-1)
