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motikmotik
3 years ago
8

Dan had a large piece of wood that was 10 feet

Mathematics
1 answer:
Doss [256]3 years ago
7 0

Answer:

40 pieces of wood

Step-by-step explanation:

Find how many pieces he cut by dividing 10 by 1/4

10 / (1/4)

= 40

So, Dan cut 40 pieces of wood

You might be interested in
What is the density of an object having a mass of 25 g and a volume of 8.0 cm cubed
weqwewe [10]

Answer:

3.125 g/cm³.

Step-by-step explanation:

The formula for density/mass/volume is d = m/v, where d is density in grams per cm cubed, m is in grams, and v is in cm cubed.

In this case, m = 25 and v = 8.0.

d = 25 / 8.0

d = 25 / 8

d = 3.125.

So, the density of the object is 3.125 g/cm cubed.

Hope this helps!

6 0
3 years ago
Solve the following quadratics. State the FACTORS AND SOLUTIONS. 1. 2x^2 - 7x + 3 2. 3x^2 + 7x +2
tekilochka [14]

Answer:

1. x = 3, 1/2 (solutions); (x - 3)(2x - 1) (factors)

2. x = -1/3, -2 (solutions); (3x + 1)(x + 2) (factors)

Step-by-step explanation:

<u>1. 2x^2 - 7x + 3</u>

To solve problem 1, you will need to identify your a, b, and c values in this quadratic function.

Since this problem is in standard form, it will be easy to identify these values. The standard form of a quadratic function is ax^2 + bx + c.

The a value is 2, the b value is -7, and the c value is 3 if we use our standard form and see which numbers are plugged into it.

Since we know that

  • a = 2
  • b = -7
  • c = 3

we can use the quadratic formula: x = \frac{-b~\pm~\sqrt{b^2~-~4ac} }{2a}

Substitute the a, b, and c values into the quadratic formula: x=\frac{-(-7)\pm\sqrt{(-7)^2-4(2)(3)} }{2(2)}

Now simplify using the laws of pemdas: x=\frac{7\pm\sqrt{(49)-(24)} }{4}

Simplify even further: x=\frac{7\pm\sqrt{(25)} }{4} \rightarrow x=\frac{7\pm (5) }{4}

Now split this equation into two equations to solve for x: x=\frac{12 }{4} ~~and~~ x=\frac{2 }{4}

12/4 can be simplified to 3, and 2/4 can be simplified to 1/2.

This means your solutions to problem 1 is 3, 1/2.

\boxed {x=3,\frac{1}{2} }

There is also another way to solve for the quadratic functions, and this was by factoring.

If you factor 2x^2 - 7x + 3 using the bottoms-up method, you will get (x - 3)(2x - 1).

After factoring, solving for the solutions is simple because all you have to do is set each factor to 0.

  • x - 3 = 0
  • 2x - 1 = 0

After solving for x by adding 3 to both sides, or by adding 1 to both sides then dividing by 2, you will end up with the same solutions: x = 3 and x = 1/2.

<u>2. 3x^2 + 7x + 2</u>

To save time I'll be using the bottoms-up factoring method, but remember to refer back to problem 1 (quadratic formula) if you prefer that method.

Factor this quadratic function using the bottoms-up method. After factoring you will have (3x + 1)(x + 2). These are your factors.

Now to solve for x and find the solutions of the quadratic function, you will set both factors equal to 0.

  • 3x + 1 = 0
  • x + 2 = 0

Solve.

<u>First factor:</u> 3x + 1 = 0

Subtract 1 from both sides.

3x = -1

Divide both sides by 3.

x = -1/3

<u>Second factor:</u> x + 2 = 0

Subtract 2 from both sides.

x = -2

Your solutions are x = -1/3 and x = -2.

\boxed {x = -\frac{1}{3} , -2}

7 0
3 years ago
I cannot understand this please help ​
vaieri [72.5K]

Answer:

28 is the answers of the question

7 0
3 years ago
The weight of an object on the moon is
Tanzania [10]

Answer:

40 2/5Ibs or 40\frac{2}{5} lbs

Step-by-step explanation:

Let weight of object on the moon be represented = Wm

weight of object on the Earth = We

In the above question, we are told:

The weight of an object on the moon is

5 of its weight on Earth.

Hence, mathematically, this is represented as:

 5Wm = We

If a moon rock weighs 202 lbs on Earth

5Wm = 202lbs

Wm = 202lbs/5

Wm = 40\frac{2}{5}Ibs

Therefore, the moon rock weighs 40\frac{2}{5}Ibs on the moon.

7 0
3 years ago
A student wants to report on the number of meals his friends buy each week. The collected data are below: 4 19 3 3 2 3 2 4 Which
Naddik [55]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
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