the answer is 3
but a way to work these problems out is to use PEMDAS
p-parentheses
e-exponent
m-multiplication
d-division
a-addition
s-subtraction
they have to be donr in that order or the answer will come out different
Answer:
2/3
Step-by-step explanation:
im pretty sure that's the answer
Consider the equation y = x^2. No matter what x happens to be, the result y will never be negative even if x is negative. Example: x = -3 leads to y = x^2 = (-3)^2 = 9 which is positive.
Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.
Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.
D is correct I believe since the values has an outlier it automatically gets rid of using mean. The dots are somewhat symmetrical. And for something to be skewed the dots are to be “connected”
Ok so, I assume this is 6 times 501
501
x 6
-------------
3006
5 x 6 = 30
6 x 0 = 0
6 x 1 = 6
