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miss Akunina [59]

3 years ago

10

Tina has $220 in her account. Cliff has $100 in his account. Starting in July, Tina adds $25 to her account on the first of each

month, while Cliff adds $35 to his. How many dollars will they have in their accounts when the amounts are the same

2 answers:

motikmotik3 years ago

6 0

The answer is 450 that’s how much it’ll be if they had the same

VLD [36.1K]3 years ago

4 0

Answer:

Both accounts will have $450

Step-by-step explanation:

Tina y= 25x+220

Cliff y= 35x+100

we can use substitution to solve this problem so the formatting would be:

25x+220=35x+100

subtract 25x from both sides

220=10x+100

Subtract 100 from both sides

120=10x

Divide both sides by 10

12=x

now that we have an x value we can plug it into either equation.

y=100+35(10)

y=100+350

y=450

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What does x equal x + 3 ≤ –5 + 2x

Anna [14]

X+3≤ -5+2x

Add 5 to the other side. (the inverse of subtraction, since 5 is negative)

x+8≤2x

Subtract x on both sides.

8≤x <- the answer

I hope this helps!
~kaikers

8 0

4 years ago

A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen

creativ13 [48]

Answer:

$Pr = 0.4286$

Step-by-step explanation:

Given

Let

$U \to\\$ Undergraduates

$G \to$ Graduates

So, we have:

$U = 3; G =5$ -- Total students

$r = 4$ --- students to select

Required

$P(U =2)$

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$Total = ^{U + G}C_r$

$Total = ^{3 + 5}C_4$

$Total = ^8C_4$

$Total = \frac{8!}{(8-4)!4!}$

$Total = \frac{8!}{4!4!}$

Using a calculator, we have:

$Total = 70$

The number of ways of selecting 2 from 3 undergraduates is:

$U = ^3C_2$

$U = \frac{3!}{(3-2)!2!}$

$U = \frac{3!}{1!2!}$

$U = 3$

The number of ways of selecting 2 from 5 graduates is:

$G = ^5C_2$

$G = \frac{5!}{(5-2)!2!}$

$G = \frac{5!}{3!2!}$

$G =10$

So, the probability is:

$Pr = \frac{G * U}{Total}$

$Pr = \frac{10*3}{70}$

$Pr = \frac{30}{70}$

$Pr = 0.4286$

5 0

3 years ago

What is the average rate of change of f over the interval -7 < or equal to x Give an exact number

Annette [7]

Answer:

$\frac{4}{3}$

Step-by-step explanation:

The average rate of change can be found by using the following formula

$\frac{f(x_{2}) - f(x_{1}) }{x_{2} - x_{1}}$

Since the interval goes from -7 to 2, we should find the y-values that correspond to x=-7 and x=2.

By inspection of the graph, we can clearly see that when x is -7, y is -7 as well and when x is 2, y is 5.

Now that we know this, we can simply plug these values into the formula!

$\frac{f(2) - f(-7) }{2 - (-7)} = \frac{5 - (-7)}{2 - (-7)} = \frac{5 +7}{2+7} = \frac{12}{9} = \frac{4}{3}$

Good luck!

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3 years ago

Speed=60 km/h time= 2 hours 20 minutes, what is the distance?

daser333 [38]

Answer:

26km

Step-by-step explanation:

d=speed × time

d=60×2.33

d= 140km

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The nine cats in a pet store were weighed. Their weights (in pounds) are given below.

stepladder [879]

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4 years ago