Answer:
value of QZ = 8 units and QM = 12 units.
Step-by-step explanation:
Given: In triangle PQR has medians QM and PN that intersect at Z.
If ZM = 4 units.
In the figure given below; second median divided the two triangles formed by the first median in the ratio 2:1.
We have to find the value of QZ and QM;
QZ:ZM = 2: 1
⇒
Substitute the value of ZM =4 units and solve for QZ;
Multiply both sides by 4 we get;
Now, calculate QM;
QM = QZ+ZM = 8 + 4 = 12 units.
Therefore, the value of QZ and QM are; 8 units and 12 units
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Answer:
false- its 4/6
Step-by-step explanation:
Answer:
three
Step-by-step explanation:
-x^2+105x-1050=1550
We move all terms to the left:
-x^2+105x-1050-(1550)=0
We add all the numbers together, and all the variables
-1x^2+105x-2600=0
a = -1; b = 105; c = -2600;
Δ = b2-4ac
Δ = 1052-4·(-1)·(-2600)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
<span><span>x1</span>=<span><span>−b−<span>Δ√</span></span><span>2a</span></span></span><span><span>x2</span>=<span><span>−b+<span>Δ√</span></span><span>2a</span></span></span>
<span><span>Δ<span>−−</span>√</span>=<span>625<span>−−−</span>√</span>=25</span>
<span><span>x1</span>=<span><span>−b−<span>Δ√</span></span><span>2a</span></span>=<span><span>−(105)−25</span><span>2∗−1</span></span>=<span><span>−130</span><span>−2</span></span>=+65</span>
<span><span><span>x2</span>=<span><span>−b+<span>Δ√</span></span><span>2a</span></span>=<span><span>−(105)+25</span><span>2∗−1</span></span>=<span><span>−80</span><span>−2</span></span>=+40</span></span>
