Answer:
x = (-5)/3
Step-by-step explanation:
Solve for x:
19 - 6 x = 29
Hint: | Isolate terms with x to the left hand side.
Subtract 19 from both sides:
(19 - 19) - 6 x = 29 - 19
Hint: | Look for the difference of two identical terms.
19 - 19 = 0:
-6 x = 29 - 19
Hint: | Evaluate 29 - 19.
29 - 19 = 10:
-6 x = 10
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of -6 x = 10 by -6:
(-6 x)/(-6) = 10/(-6)
Hint: | Any nonzero number divided by itself is one.
(-6)/(-6) = 1:
x = 10/(-6)
Hint: | Reduce 10/(-6) to lowest terms. Start by finding the GCD of 10 and -6.
The gcd of 10 and -6 is 2, so 10/(-6) = (2×5)/(2 (-3)) = 2/2×5/(-3) = 5/(-3):
x = 5/(-3)
Hint: | Simplify the sign of 5/(-3).
Multiply numerator and denominator of 5/(-3) by -1:
Answer: x = (-5)/3
If that is what it looks like it is, 12 divided by -6 is -2, the a's cancel out, the y's cancel out, and you're left with -2b. I'm not sure what else this could be.
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
(-32/7,281/21) is the answer
Brainliest?
