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yarga [219]
2 years ago
13

Find the area of a circle whose area equals the half of the sum of the areas of two circles with radil 2 and 3.

Mathematics
1 answer:
OlgaM077 [116]2 years ago
8 0

Step-by-step explanation:

step 1. a circle with r = 2 has area of (pi)r^2 = (pi)(4) = 4pi

step 2. a circle with r = 3 has area of (pi)r^2 = (pi)(9) = 9pi

step 3. the area, A, of a circle is half the sum of the area of the circles with r = 2 and r = 3

step 4. A = (4pi + 9pi)/2 = 13pi/2 = 6.5(pi).

step 5. the answer is not 6.5 but is 6.5(pi) or 6.5 times pi.

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X
sergeinik [125]

Answer:

A. x = 58°

B. x = 10m

C. a = 44°

All approximated to nearest whole number.

Step-by-step explanation:

All triangles given are right angled triangles. Therefore, we would apply the trigonometry functions to solve for each missing side and angle.

Recall: SOHCAHTOA

a. Adjacent = 4.8cm,

Hypotenuse = 9cm

Angle to find =x°

Thus, we would apply the following formula:

Cos θ = Adjacent/Hypotenuse

Cos θ = 4.8/9 = 0.5333

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b. Opposite side = x

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Sine θ = opposite/hypothenuse

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