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2 years ago

Round 75.434 to the nearest hundredth

Mathematics

2 answers:

nordsb [41]2 years ago

4 0

Answer:75.43

Explanation:

satela [25.4K]2 years ago

4 0

75.43
I’m sure it’s right but not. oof.

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On a deposit of $2,500 that earns 1% compound interest (compounded annually), how much will you have after 6 years?

guajiro [1.7K]

Answer:

You would have $4428.90 after 6 years

Please mark brainliest

Step-by-step explanation:

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3 years ago

Help guys make p da subject of the formula

Basile [38]

Answer:

$p=\dfrac{m}{k-s}$

Step-by-step explanation:

When they ask you to make a variable the "subject of the formula", they're basically asking you to build a "machine" for it. In the expression $y=mx+b$ , for instance, if we know what m, x, and b are, we can plug them all in and out comes a value for y! To build that machine, we need to get it by itself on one side of the equation.

So, we want to build this machine for p, and the equation we have to build it out of is

$1=\dfrac{pk}{m+sp}$

One think we can immediately say about this equation: for a fraction to be equal to one, its numerator and denominator have to be equal to each other. So we can say

$m+sp=pk$

Ok, what next? Well, if we want p by itself, we need to somehow peel it off of that sp and pk. Let's collect them on the right side by subtracting sp from both sides:

$m=pk-sp$

p is a common factor of both sp and pk, so we can peel it away using the distributive property:

$m=p(k-s)$

And from here, we can divide both sides by $k-s$ and we'll have p as our subject:

$\dfrac{m}{k-s}=p$ or $p=\dfrac{m}{k-s}$

So if we know m, k, and s, we can easily solve for p. If m = 4, k = 2, and s = 0:

$p=\frac{4}{2-0} =\frac{4}{2}=2$

3 0

3 years ago

Express 4 cm as a fraction of 2 m

Amanda [17]

2m = 200cm

4/200

divide both sides by 4:
1/50

Hope this helps ^-^

3 0

3 years ago

How many of these equations have the solution 2 = 12?

tino4ka555 [31]

Step-by-step explanation

i don't understand option B

3 0

3 years ago

A. Create a set of 5 points that are very close together and record the standard deviation. Next, add a sixth point that is far

defon

Answer: The addition of the new point alters the previous standard deviation greatly

Step-by-step explanation:

Let the initial five points be : 2 3 4 5 and 6. In order to calculate the standard deviation for this data, we will need to calculate the mean first.

Mean = summation of scores/number of scores.

The mean is therefore: (2+3+4+5+6)/5 = 20/5 = 4.

We'll also need the sum of the squares of the deviations of the mean from all the scores.

Since mean = 4, deviation of the mean from the score "2" = score(2) - mean (4)

For score 3, it is -1

For 4, it's 0

For 5 it's 1

For 6 it's 2.

The squares for -2, -1, 0, 1, and 2 respectively will be 4, 1 , 0, 1, 4. Summing them up we have 10 i.e (4+1+0+1+4=10).

Calculating the standard deviation, we apply the formula:

√(summation of (x - deviation of mean)^2)/N

Where N means the number of scores.

The standard deviation = √(10/5) = 1.4142

If we add another score or point that is far away from the original points, say 40, what happens to the standard deviation. Let's calculate to find out.

i.e we now have scores: 2, 3, 4, 5, 6 and 40

We calculate by undergoing same steps.

Firstly mean. The new mean = (2+3+4+5+6+40)/6 = 60/6 = 10.

The mean deviations for the scores : 2, 3, 4, 5, 6 and 40 are -8, -7, -6, -5, -4 and 30 respectively. The squares of these deviations are also 64, 49, 36, 25, 16 and 900 respectively as well. Their sum will then be 1090. i.e. (64+49+36+25+16+900 = 1090).

The new standard deviation is then=

√(1090/6)

= √181.67

= 13.478.

It's clear that the addition of a point that's far away from the original points greatly alters the size of the standard deviation as seen /witnessed in this particular instance where the standard deviation rises from 1.412 to 13.478

7 0

3 years ago