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lilavasa [31]
3 years ago
5

Please help me with this please help!

Mathematics
1 answer:
Basile [38]3 years ago
3 0

Answersharaddhagupta become my friend

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I don't think i've been so confused ever, how do I solve this using long division?
tankabanditka [31]

Check the picture below.

7 0
3 years ago
It took team rise over run 1 2/3 hours to hike 4 2/3 miles. What is their average speed in miles per hour?
pogonyaev

To find their average miles per hour we can divide the total miles by the hour used:

4 2/3 ÷ 1 2/3

=4x3+2/3 ÷ 1x3+2/3

=14/3 ÷ 5/3

In division, when we switch the place of numerator and denominator, we can change it to multiplication which makes the calculation easier as we can factorize the numbers.

=14/3 x 3/5

Factorize 3 in both amounts:

=14/1 x 5/1

=14/5

=2.8 miles/hour

Therefore their average speed is 2.8 miles/hour.

Hope it helps!

8 0
3 years ago
Determine in which quadrant the product of 5(cos3pi/8 + isin 3pi/8) and sqrt 2(cos pi/12 + sin pi/12) lies.
ohaa [14]
When you multiply two complex numbers given in polar form, the argument of the product is the sum of the arguments of the factors. Meanwhile, the modulus of the product is the product of the moduli of the factors.


In this case, you'd have

\dfrac{3\pi}8+\dfrac\pi{12}=\dfrac{11\pi}{24}

and the modulus would simply be 5\sqrt2. Since

\dfrac{11\pi}{24}

we would expect the final product to fall in the first quadrant.
6 0
3 years ago
Find from u.<br><br> -12u = -24
Bingel [31]
Well, to find u, we have to remove all that is attached to it so the equation can just be u=...
   To find u, you have to remove what is attached to it, and that is -12. Then you have to look at the relationship between the -12 and u. The relationship is multiplication, and the opposite of multiplication is division, so all you have to do is divide both sides by -12. So;
-12u/-12=-24/-12
   The -12 cancels the -12, leaving u and the - in 12 cancels the - in 24. Leaving 24/12. And that is 2. Written as;
u=2
   Hope i helped. If you have any more problems, let me know.
5 0
3 years ago
Read 2 more answers
Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
ycow [4]

Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

4 0
3 years ago
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