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inessss [21]
3 years ago
9

At the amusement park, each student is given $16 for food. This covers the cost of 2 meals plus $4 for snacks. How much money do

es the school expect each student to spend per meal?
Answers:
4 - 2m = 16
4m - 2 = 16
2m + 4 = 16
4m - 16 = 2
Mathematics
1 answer:
TEA [102]3 years ago
3 0
So 'm' represents the cost of a meal, since the student is expected to buy 2 of them, the coefficient on the 'm' is 2. They are also budgeted $4 for snacks, so the total amount of money they can spend is 2 meals + $4 for snacks, which cannot be greater than 16. 
2m+4=16.
m=6 dollars
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Is -1/8 greater than -1/10
Alika [10]

Answer:

false

Step-by-step explanation:

-1/8 = -0.125

-1/10 = -0.1<u>00</u>

as it is negative  

-0.125 < -0.1

so it is false

8 0
3 years ago
During the course of working on a wiring job, an electrician checks out the following cable stocks from the storeroom: 5 reels,
grin007 [14]

A)The reels did the electrician check out from the storeroom is 16 reels.

B) 800 feet of cable were checked our from the storeroom, if each reel has 50 feet of wire.

C) 730  feet of cable did the electrician use on the job.

Given that during the course of working on a wiring job, an electrician checks out the following cable stocks from the storeroom: 5 reels, 3 reels, 1 reel, 3 reels, and 4 reels. at the end pf the job he returns to the storeroom 1 full reel and a partial reel with 20 feet remaining.

The total number of reels are 16 in the store room and each reel is of 50 feet . As a result total reel has 800 feet and at last he left with 1 reel and 20 feet reels so that reel that left is 730 feet

Therefore,A)The reels did the electrician check out from the storeroom is 16 reels.

B) 800 feet of cable were checked our from the storeroom, if each reel has 50 feet of wire.

C) 730  feet of cable did the electrician use on the job.

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brainly.com/question/15658113

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5 0
1 year ago
#5 Need help with this
olganol [36]

Answer:

Maple grove associates

Step-by-step explanation:

8 0
3 years ago
A light-year is the distance light travels in one year, about 5.9×1012 mi. Earth is located about 25,000 light-years from the Mi
vaieri [72.5K]

Answer:

1.475 × 10¹⁴ mi

Step-by-step explanation:

Since  1 light year = 5.9 × 10⁹ mi and the Earth is located about 25,000 light-years from the Milky Way's rim, the approximate distance, in miles, from Earth to the rim of the Milky Way is 25,000 light year = 25,000 × 1 light year

= 25,000 × 5.9 × 10⁹ mi

= 147.5 × 10¹² mi

= 1.475 × 10¹⁴ mi

3 0
2 years ago
Use the transforms in section 4.1 to find the Laplace transform of the function. t^3/2 - e^-10t
Delvig [45]

Answer:

Laplace transformation of L(t^\frac{3}{2}-e^{-10t})=\frac{3\sqrt{\pi} }{4 s^\frac{5}{2} }\ -\frac{1}{s+10}

Step-by-step explanation:

Laplace transformation of L(t^\frac{3}{2}-e^{-10t}  )

L(t^\frac{3}{2})=\int_{0 }^{\infty}t^\frac{3}{2}e^{-st}dt\\substitute \ u =st\\L(t^\frac{3}{2})=\int_{0 }^{\infty}\frac{u}{s} ^\frac{3}{2}e^{-u}\frac{du}{s}=\frac{1}{s^{\frac{5}{2}}}\int_{0 }^{\infty}{u} ^\frac{3}{2}e^{-u}{du}

the integral is now in gamma function form

\frac{1}{s^{\frac{5}{2}}}\int_{0 }^{\infty}{u} ^\frac{3}{2}e^{-u}{du}=\frac{1}{s^{\frac{5}{2}}}\Gamma(\frac{5}{2})=\frac{1}{s^{\frac{5}{2}}}\times\frac{3}{2}\times\frac{1}{2} }\Gamma (\frac{1}{2} )=\frac{3\sqrt{\pi} }{4 s^\frac{5}{2} }

now laplace of L(e^{-10t})

L(e^{-10t})=\frac{1}{s+10}

hence

Laplace transformation of L(t^\frac{3}{2}-e^{-10t})=\frac{3\sqrt{\pi} }{4 s^\frac{5}{2} }\ -\frac{1}{s+10}

3 0
3 years ago
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