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inessss [21]
4 years ago
9

At the amusement park, each student is given $16 for food. This covers the cost of 2 meals plus $4 for snacks. How much money do

es the school expect each student to spend per meal?
Answers:
4 - 2m = 16
4m - 2 = 16
2m + 4 = 16
4m - 16 = 2
Mathematics
1 answer:
TEA [102]4 years ago
3 0
So 'm' represents the cost of a meal, since the student is expected to buy 2 of them, the coefficient on the 'm' is 2. They are also budgeted $4 for snacks, so the total amount of money they can spend is 2 meals + $4 for snacks, which cannot be greater than 16. 
2m+4=16.
m=6 dollars
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Answer:

The probability that the sample will contain exactly 0 nonconforming units is P=0.25.

The probability that the sample will contain exactly 1 nonconforming units is P=0.51.

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Step-by-step explanation:

We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.

We can write the probability mass function as:

P(x=k)=\frac{\binom{K}{k}\binom{N-K}{n-k}}{\binom{N}{n}}

where k is the number of non-conforming units on the sample of n=4.

We can calculate the probability of getting no non-conforming units (k=0) as:

P(x=0)=\frac{\binom{3}{0}\binom{9}{4}}{\binom{12}{4}}=\frac{1*126}{495}=\frac{126}{495} = 0.25

We can calculate the probability of getting one non-conforming units (k=1) as:

P(x=1)=\frac{\binom{3}{1}\binom{9}{3}}{\binom{12}{4}}=\frac{3*84}{495}=\frac{252}{495} = 0.51

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