Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Answer:
12 - (⅛)π cm²
Step-by-step explanation:
Rectangle + circle - semicircle
(4 × 3) + (pi × 1²) - ½(pi × 1.5²)
12 + pi(1 - 9/8)
12 - (⅛)π
Answer:
Hey
Step-by-step explanation:
I bevlive your answer is B. If you multiply the two numbers you get 1.4
Answer:
2/6
Step-by-step explanation:
Each of the rectangle strips are taped together to form a rectangle. Therefore 1 of the third of the rectangle would be red, this means that 1/3 of the rectangle would be red color. The rectangle is then divide into sixths, this can be achieved by dividing each of the taped strip into 2.
Therefore 2 of the sixths rectangle would be red in color, Hence the fraction of the rectangle that would be red is given as 2/6
