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Evgesh-ka [11]
3 years ago
14

Which pair of fractions is not equivalent fractions?

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0
B. Is correct. I just did this
olganol [36]3 years ago
6 0
B because all of the other ones are correct-
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→ PLEASE HELP ME! [99 POINTS] ←
zaharov [31]
B.

The cost for x children and y adults to go to the movies if adult tickets are $11 and child tickets are $6.

Example 3 children and 2 adults ( 6(3) + 11(2) )
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Solve. u+6 = 18<br> a. 3<br> b. 12<br> c. 24<br> d. 108
Gekata [30.6K]
u+6=18\\&#10;u=12
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3 years ago
Amanda lives in Fairbanks Alaska she records the low temperature for five days, which days low temperature was 9c colder than th
Brrunno [24]

Answer: all of them they are negitive numbers

Step-by-step explanation:

3 0
3 years ago
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Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
Michael took in 91 mile bike trip. he left home at 7 AM. If he stopped for a total of two hours for rest and food and averaged 1
Korvikt [17]
Distance = rate * time
t = d / r

t = 91 / 14 = 6.5 hrs

plus 2 hour rest stop

8.5 hrs

start at 7 AM
end at 3:30 PM
5 0
3 years ago
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