In order to begin we must start off with the formula for the area of a triangle, which is a=1/2b(h) where a is area, b is base, and h is height.
In this scenario, we know that the area is 45cm^2 and the base is 2h+12 (since it is twice it’s height plus twelve). We can plug this into the area equation and then proceed to solve out accordingly.
a=1/2b(h)
45=1/2(2h+12)(h)
90=(2h+12)(h)
90=2h^2 + 12h
0= 2h^2 + 12h - 90
Simplify by dividing the two out.
h^2 + 6h - 45 = 0.
Now plug into the quadratic formula (with a=1, b=6, and c=-45) as shown in the image below.
After plugging the equation in and solving, we come to the idea that h is roughly equal to 4.34. We can now plug this back into the triangle area formula to solve out for b.
a=1/2b(h)
45=1/2(2h + 12)(h)
45=1/2(20.69)(4.34)
45=45.
In conclusion;
The height is ≈ 4.34
The base is ≈ 8.68
Hope this helps :)
A. 2/5
B.2/5
C. The slope of ABC and AGH are equal
The output would depend on the input so relating this to the question, the input is the time (in minute) and the output is the amount of water left in the tank
We can give a letter 't' for the time, the input, and f(t) for the output
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The original amount of water in the tank is 10450, so this will be the fixed constant.
The amount of water lost per minute is 270 so this will be the term that varies depends on the variable of time, we write this as 270t
The function is given f(t) = 10450 - 270t
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Given, t = 10
f(10) = 10450 - 270(10)
f(10) = 7750 ml
3 is the remainder because the closest is 7 times 21 so it’s remainder 3
