6z -4 - z + 10 = -9
Combine like terms
5z + 6 = -9
Subtract both sides by 6
5z = -15
Divide both sides by 5
z = -3
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The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100
200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
Answer:
Plane: C) A flat surface that extends infinitively and has no depth; it has length and width
Perpendicular Lines: B) Two lines that intersect at 90° angles
Parallel Lines: E) Two lines that lie within the same plane and never intersect
Circle: D) A set of all points in a plane that are given distance from a plane
Angle: A) A figure consisting of two rays with a common endpoint
I hope this helps
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Answer:
p = 3
Step-by-step explanation:
This is an isosceles right triangle
=> 2side^2 = (hypotenuse)^2
=> 2p^2 = (3sqrt(2))^2
=> 2p^2 = 18
=> p^2 = 9
=> p = 3
Answer:
y = -2.8x +69.4
Step-by-step explanation:
Let y represent units of inventory, and x represent days since the last replenishment. We are given points (x, y) = (3, 61) and (13, 33). The line through these points can be described using the 2-point form of the equation of a line:
... y -y1 = (y2-y1)/(x2 -x1)(x -x1)
Filling in the given point values, we have ...
... y -61 = (33 -61)/(13 -3)(x -3)
Simplifying and adding 61, we get ...
... y = -2.8x +69.4
