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trapecia [35]
2 years ago
8

Evaluate: Four To The Third Power write the numerical answer only

Mathematics
1 answer:
Alja [10]2 years ago
7 0
The answer is 4^3 and I believe that this is right
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In a particularly sunny month, Solaire's solar panels generated 110 percent as much power as expected.What fraction of the expec
vfiekz [6]

we are given

In a particularly sunny month, Solaire's solar panels generated 110 percent as much power as expected.

so, we need to change percent into fraction to get our value

we can write

110%=\frac{110}{100}

now, we can simplify it

and we get

110%=\frac{11}{10}

so,

Solaire's solar panels generate \frac{11}{10} of the expected amount of power.............Answer

8 0
3 years ago
Read 2 more answers
What is 453.028 divided by sin(28) ?
DedPeter [7]

Answer:

964.97

Step-by-step explanation:

Plug the values into a calculator (Make sure your calculator is on degrees, not radians

453.028 / sin(28)

= 964.97

(If this answer helps you, please consider choosing it as the 'brainliest answer'. I would really appreciate it :)

7 0
3 years ago
The height of a kicked football can be represented by the polynomial –15t2 + 17t + 4, where t is the time in seconds. Find the f
lozanna [386]

Answer:

(−5t−1)(3t−4)

Step-by-step explanation:

Factor −15t2+17t+4

−15t2+17t+4

=(−5t−1)(3t−4)

6 0
3 years ago
Help needed!! i’m normally good with fractions but today i just can’t
Cerrena [4.2K]
Answer: for 5/6 (-8/15) = - 4/9
6 0
3 years ago
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A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base
timurjin [86]

Answer:

Step-by-step explanation:

Equation for a hyperboloid of one sheet, with center at the origen and axis along z-axis is:

(x/a)²  +  (y/b)²   -  (z/c)²  =  1                         (1)

We have to find a , b, and c

We can express equation (1)

(x/a)²  +  (y/b)²    =  (z/c)² + 1                 (2)

Now if we cut the hyperboloid with planes parallel to xy plane we get for  z = k       ( K = 1 , 2 , 3  and so on ) circles of different radius

(x/a)²  +  (y/b)²    =  (k/c)² + 1

at z = k = 0 at the base of the hyperboloid  d = 300   or r = 150 m

we have

(x/a)²  +  (y/b)²   = 1      

x²  +  y²   =   a²                a² = (150)²       a = b = 150

and    x²  +  y²  = (150)²

Now the other condition is at 200 m above the base d = 500 m   r = 250 m  minimum diameter then in equation (2)  we have:

(x/a)²  +  (y/b)²    =  (z/c)² + 1        

(1/a)² [ x² + y² ]  = (z/c)² + 1  

but   x²  +  y²  = r²    and in this case   r  =  250 m  then

(250)²/(150)²   =  (z/c)² + 1    ⇒ (62500/ 22500)  =  (200/c)² + 1

2,78  =  40000/c² + 1

2.78c²  =  40000  + c²

1.78c² = 40000

c²  =  40000/1.78

c²  = 22471.91

c = 149,91

Then we finally have the equation:

x²/(150)²   + y² /(150)² - z²/149,91  = 1

7 0
3 years ago
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